Gparker
Veteran
Now i get those stuff but when you do blinding and u solve one edges does the other piece u want next always goes to the buffer position?
once you do an edge, the edge that was there is now in your buffer
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Now i get those stuff but when you do blinding and u solve one edges does the other piece u want next always goes to the buffer position?
Impossible without you telling us your color scheme / how you hold the cube.Please give an algorithm to solve the yellow blue or the blue yellow
Oh k nvm thanks for everything its clear now i just need to know when do i need parity i learned the equation of
(#Wrong Pieces)+(#Cycles)-2 But i still dont have a clue when to use the parity algorithm
Oh k nvm thanks for everything its clear now i just need to know when do i need parity i learned the equation of
(#Wrong Pieces)+(#Cycles)-2 But i still dont have a clue when to use the parity algorithm
lets say you do the algorithm on a solved cube, the J perm for example. it switches to edges AND 2 corners. When your blindsolving the edges or corners it doesnt mattter, if you do an odd number of J/T/Y's 2 edges or corners will be swaped from which you memo, so before you start doing corners/edges after you are done with corners/edges, you need to do the R perm which is the parity alg. because if you have an odd number of corners, you will have an odd number of edges and it will all turn out normal
ODD+ODD=EVEN
Odd number of corners/edges= R perm, then continue
Oh k nvm thanks for everything its clear now i just need to know when do i need parity i learned the equation of
(#Wrong Pieces)+(#Cycles)-2 But i still dont have a clue when to use the parity algorithm
lets say you do the algorithm on a solved cube, the J perm for example. it switches to edges AND 2 corners. When your blindsolving the edges or corners it doesnt mattter, if you do an odd number of J/T/Y's 2 edges or corners will be swaped from which you memo, so before you start doing corners/edges after you are done with corners/edges, you need to do the R perm which is the parity alg. because if you have an odd number of corners, you will have an odd number of edges and it will all turn out normal
ODD+ODD=EVEN
Odd number of corners/edges= R perm, then continue
So i aware now when to do parity on a oddnumber of perms but what about cycle how do u know u need to use a cycle in a beginning of a solve?
Ok, your Buffer is UL, you see where that peice has to go and so on and so on, im guessing that you know how to know what peice goes in the buffer, when your buffer peice goes in your buffer, flipped or not, you swap it with a peice and then you remember where you put that peice at
Oh k nvm thanks for everything its clear now i just need to know when do i need parity i learned the equation of
(#Wrong Pieces)+(#Cycles)-2 But i still dont have a clue when to use the parity algorithm
lets say you do the algorithm on a solved cube, the J perm for example. it switches to edges AND 2 corners. When your blindsolving the edges or corners it doesnt mattter, if you do an odd number of J/T/Y's 2 edges or corners will be swaped from which you memo, so before you start doing corners/edges after you are done with corners/edges, you need to do the R perm which is the parity alg. because if you have an odd number of corners, you will have an odd number of edges and it will all turn out normal
ODD+ODD=EVEN
Odd number of corners/edges= R perm, then continue
So i aware now when to do parity on a oddnumber of perms but what about cycle how do u know u need to use a cycle in a beginning of a solve?
Ok, your Buffer is UL, you see where that peice has to go and so on and so on, im guessing that you know how to know what peice goes in the buffer, when your buffer peice goes in your buffer, flipped or not, you swap it with a peice and then you remember where you put that peice at: ill give you a scramble to help
White-U, Red-F
D' B2 D' U' L2 R' B F2 L2 U F' L' R' D L2 R D2 L2 U2
For edges, the first peice is the red of red blue, so you swap it out with d2 L Tperm L' d2
Then your buffer is solved, so you switch it out with any other unsolved peice and then you remember where you put it so when you end up solving the peice that you stored your buffer peice, then you break into another cycle
make sense? i can make a video tomorrow if you want