Random Blindfold Cubing Discussion

Hi! I can't figure out how to fix midge parity for 5bld. My solving order is centers -> wings -> midges -> corners. I tried the normal 3x3 parity alg but that of course breaks the two edge blocks.

I'm also not quite sure if the 4x4 wing parity works on 5x5 without damaging the midges. I've yet never tried 5bld but with some tips I could be on my way. ;)

What's your buffers for corners and midges?
 
For corners, UBL (OP)
Midges, DF (M2)

And wings DFr (r2)

My way:
Switch UBR-UBL by adding UBL as your last target to corners. Earlier correct M2 by adding BU as your last target. When you got whole cube: F2 - parity alg: (Rr2 F2 U2 r2 U2 F2 Rr2) And next y PLLT L2. I know there are some different ways but the idea is the same: to correct parity on big cubes you must include parity alg for big cubes. In case of 5bld you can have as well parity on your wings. I solve it with the same alg as in 4bld.
 
My way:
Switch UBR-UBL by adding UBL as your last target to corners. Earlier correct M2 by adding BU as your last target. When you got whole cube: F2 - parity alg: (Rr2 F2 U2 r2 U2 F2 Rr2) And next y PLLT L2. I know there are some different ways but the idea is the same: to correct parity on big cubes you must include parity alg for big cubes. In case of 5bld you can have as well parity on your wings. I solve it with the same alg as in 4bld.
What do you mean by doing UBL as the last target as it is the buffer?
 
Sorry - I ment: last target - UBR - UBL. :) If you do OP corners you do: last target, next UBR as a target. This switches UBR and UBL and corrects UB and UL like in standard OP on 3x3.
 
Hi! I can't figure out how to fix midge parity for 5bld. My solving order is centers -> wings -> midges -> corners. I tried the normal 3x3 parity alg but that of course breaks the two edge blocks.
Do normal M2 parity for midges but insert @h2f's alg to swap the wings alongside them.

D' L2 D M2 (F2 (Rw2 F2 U2 r2 U2 F2 Rw2) F2) D' L2 D
 
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Can someone tell me the pros and cons of having DFR as your buffer using 3style? I know it involves more 'R' 'U' 'D' algs but anything else?
not true to me, by 5 cases, but still not true
ofc the ammount of xUD algs would be the same for the 8 corners, i dont know if U corners have more D turns or the other way around
for corner flips R corners defenetly more RUD than LUD algs, and D corners defenetly more U turns than D turns, so in that regard i personally prefer DBR and DFR equally
if you use a D layer corner as a buffer you would have to look at that corner only once per scramble, so you wont have to do x2 during memo, i guess you can count that as a pro xd
the biggest con is you want adjacent buffers, and U layer edge buffers are best by far
 
Random question, I remember someone once posted a list comparing Big Blind attempts to multi blind based on the amount information you are required to memo for example:

4x4 BLD = about 2.3 3x3's
5x5 BLD = about 5.6 3x3's (I think?)

Can someone link me to this list or create a similar one, thank you.
 
Random question, I remember someone once posted a list comparing Big Blind attempts to multi blind based on the amount information you are required to memo for example:

4x4 BLD = about 2.3 3x3's
5x5 BLD = about 5.6 3x3's (I think?)

Can someone link me to this list or create a similar one, thank you.
4BLD = about 2.4 3x3s
5BLD = about 4.25 3x3s
 
Oof. For the past 3 days I feel like I unlearned BLD.

My execution has been so bad I'm starting to find new ways to scramble the cube, and my memo is constantly messy.

/rant over, back to practice
 
I want a list that continues into bigger cubes up to 10x10. (just for reference ;))
I suggest approx. (n^3-(n-2)^3-3*n)*(1-(n-3)/100)/19
the ^3-thingings to find the number of pieces, the 3*n to substract the middle-pieces and lucky placed pieces for odd n and the placed pieces after a good orientation for even n, the 1-(n-3)/100 for more centers on bigger cubes and so bigger possibility for placed pieces and the 19 for approx. 11,5 edges and 7,5 corners on a 3x3.
:D
 
I suggest approx. (n^3-(n-2)^3-3*n)*(1-(n-3)/100)/19
the ^3-thingings to find the number of pieces, the 3*n to substract the middle-pieces and lucky placed pieces for odd n and the placed pieces after a good orientation for even n, the 1-(n-3)/100 for more centers on bigger cubes and so bigger possibility for placed pieces and the 19 for approx. 11,5 edges and 7,5 corners on a 3x3.
:D
I think you are missing a parentheses around here

(n^3-(n-2)^3-3*n)*(1-((n-3)/100)/19

also these numbers are coming out to be slightly different than the ones that @CyanSandwich mentioned. I'm getting 2.29 for 4BLD and 5.125 for 5BLD
 
I think you are missing a parentheses around here
(n^3-(n-2)^3-3*n)*(1-((n-3)/100)/19
also these numbers are coming out to be slightly different than the ones that @CyanSandwich mentioned. I'm getting 2.29 for 4BLD and 5.125 for 5BLD

5 open parentheses and 4 closing? I think, that I did them right. And I get for n=5:
(5*5*5-3*3*3-3*5)*0,98/19=4,28

So that's quite close to CyanSandwich and he said "about" and I said "approx." and for all other miscalculations I added the biggrin in the end :p
 
Oof. For the past 3 days I feel like I unlearned BLD.

My execution has been so bad I'm starting to find new ways to scramble the cube, and my memo is constantly messy.

/rant over, back to practice
taking a break always helped me to improve at stuff
 
taking a break always helped me to improve at stuff

I kept going and voila: First sub-60 single xD

(But seriously, got a comp this coming Sunday and I'll be damned if I don't get an official single this time around. Also I have a slight chance of podium, so there's that lol)
 
ok i have a new megaBLD memo method that doesn't rely on colors or languages. It's kinda like the ben system for cards. the way it works is 2 targets are encoded into a consonant-vowel-consonant unit

there are 12 faces on a megaminx, and you can divide them into 3 groups of 4 faces. Each of 20 stickers in a group is given a consonant (B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, V, W, Y, Z).
Since you have 2 targets per unit, and there are 3 groups, there are 3*3=9 total combinations of groups, which can be encoded into vowels (a, e, i, o, u, oo, ay, ee, ai)

To construct an image (or audio sound, it doesn't matter):
1. find the consonant that corresponds to the first target
2. find which of the 3 groups each target belongs to, and then encode that info into one of 9 vowels
3. find the consonant that corresponds to the second target

then form an image

i think this system is good, but sorry if i didn't explain well. i might make a video if ppl want

EDIT: i've never even attempted megaBLD before, so idk how well this system works but it just looks efficient to me
 
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