# CxLL L L

## L L

The four cases, U R, U L, L L and L F are mirrors and inverses of each other so the same algorithm (9 move commutator) can be used to solve them all.

First look in the U-face, there are two stickers of the same colour, next find the two stickers of the opposite colour. Case L F looks the same but mirrored. |

### COLL

- (y) R U2 R D R' U2 R D' R2

### CLL

- ...

### CMLL

- R U2 L' U' L U2 R' U R' F2 R

### CLLEF

- y' R U R' U R' F R F' U2 R' F R F'

### CF / 2x2x2 (Waterman)

- ...

### EG

**EG 2** --> 2x2x2

**EG 1**

- ...

**EG 0**

- y R'UR'F'U'FUF2R2

CxLLedit |
U |
D |
R |
L |
F |
B |

U |
U U |
U D |
U R |
U L |
U F |
U B |

T |
T U |
T D |
T R |
T L |
T F |
T B |

L |
L U |
L D |
L R |
L L |
L F |
L B |

S |
S U |
S D |
S R |
S L |
S F |
S B |

-S |
-S U |
-S D |
-S R |
-S L |
-S F |
-S B |

Pi |
Pi U |
Pi D |
Pi R |
Pi L |
Pi F |
Pi B |

H |
H U |
H D |
H R |
H L |
H F |
H B |

Hyper CLLedit |
U |
D |
R |
L |
F |
B |

U |
U U |
U D |
U R |
U L |
U F |
U B |

T |
T U |
T D |
T R |
T L |
T F |
T B |

L |
L U |
L D |
L R |
L L |
L F |
L B |

S |
S U |
S D |
S R |
S L |
S F |
S B |

-S |
-S U |
-S D |
-S R |
-S L |
-S F |
-S B |

Pi |
Pi U |
Pi D |
Pi R |
Pi L |
Pi F |
Pi B |

H |
H U |
H D |
H R |
H L |
H F |
H B |