World Championship 2007

[Ron]

Check out http://www.worldcubeassociation.org/results/c.php?allResults=All+Results&competitionId=WC2005
and see which events you could have won if you were as good as you are now.
Especially 2x2 and 5x5 would be piece of cake.

 

[AvGalen]

Nice first post on this forum Ron! I hope we will see you here often.

Does some nice person want to cancel on Multiple Blindfolded so Arnaud can go for the new world record?

I plan on doing 5/5 or 6/6 so there is no way that I could beat the world record. However I might just win if the real experts all do 10/11 or 19/20 or so. I don't think that is entirely impossible. In some multiple blindfold competitions it would have been enough to:

1) Ask for 2 cubes
2) Only study 1 cube
3) Only solve 1 cube
4) Win the event with 1/2 cubes in just a couple of minutes.

 

[pjk]

I am guessing the Multi-BLD event winner will do 15/15 Just a guess....

 

[AvGalen]

I think the real multi-blind-experts will want to tell how many they are attempting in secret. Otherwise Row might just hear Mátyás will do 12 and then he will do 13.

 

[Mátyás Kuti(shaipo)]

I think the real multi-blind-experts will want to tell how many they are attempting in secret. Otherwise Row might just hear Mátyás will do 12 and then he will do 13.

I'll do 18. Rowe will do (maximum) 17.
We have already discussed it. xD

 

[tim]

I think the real multi-blind-experts will want to tell how many they are attempting in secret. Otherwise Row might just hear Mátyás will do 12 and then he will do 13.

I'll do 18. Rowe will do (maximum) 17.
We have already discussed it. xD

And you guys can trust each other?

I thought 10 - 13 would be enough to win this event. 18 cubes are crazy . If one of you will get this, i'll stop practicing for the multi-blind world record :/.

 

[AvGalen]

What if you only get 1 attempt? Would you guys try 17/18 cubes also and risk me winning with a 2/2?

 

[AvGalen]

After Ron's post about the WC2005 I digged a little and found this story of the EC2006 by Erik. You will be amazed how much has (and hasn't) changed in just 1 year

http://erikku.er.funpic.org/rubik/euro2006.html

 

[Stefan]

What if you only get 1 attempt?

What do you mean, "if" ?

 

[AvGalen]

That was my subtle way of pointing out to everyone that you only get one attempt. That means that for 17 cubes at roughly 200 moves per cube you cannot make a single wrong move out of 3400 moves or else you could get beaten by a beginner (like me) that chooses to do 2/2 and does it correctly in 29:59.99.

 

[Erik]

After Ron's post about the WC2005 I digged a little and found this story of the EC2006 by Erik. You will be amazed how much has (and hasn't) changed in just 1 year

http://erikku.er.funpic.org/rubik/euro2006.html

I found the following sentences quite funny now:
'Gilles has became very fast in OH cubing. Best avg below 30 sec!'
'I started fairly good with a 17.66' (3x3)
'the 3rd was better 2:04.88NR' (minx)
'I manage a sub-4min, but I got a 4:27.78' (5x5)
'ER average of 29.09!' (gilles on OH)
'Anssi won with an amazing time of 1:25.63' (3x3 feet)
'won with 14.97 ' (Joel on 3x3 finals)
also what was the solution to this riddle of Guus again? 'you have the digits 1, 3, 4 and 6. By dividing, multiplying adding and the other thing of which I don't know the english name whe had to make 24'
I forgot

 

[Stefan]

That means that for 17 cubes at roughly 200 moves per cube you cannot make a single wrong move out of 3400 moves

And Matyas did make a mistake before, in one of the 52 cubes he attempted in competitions so far.

 

[Stefan]

also what was the solution to this riddle of Guus again? 'you have the digits 1, 3, 4 and 6. By dividing, multiplying adding and the other thing of which I don't know the english name whe had to make 24

It's called "subtract". And there are at least two answers. I asked it at the US Open and Tyson found the answer I knew, while Shelley and Toby found another one.

 

[DanHarris]

By dividing, multiplying adding and the other thing of which I don't know the english name whe had to make 24'
I forgot

Subtracting!

 

[DanHarris]

sheesh, stefan got his post in inbetween me viewing this page and me refreshing this page to see my post. Git.

 

[AvGalen]

I think this should be correct: 6 / (1-(3/4))
1-3/4 = 0.25
6/0.25 = 24

 

[Stefan]

I just noticed I presented the riddle with the numbers 1, 4, 5, 6. I don't see a second solution with 1, 3, 4, 6.

 

[Pedro]

That was my subtle way of pointing out to everyone that you only get one attempt. That means that for 17 cubes at roughly 200 moves per cube you cannot make a single wrong move out of 3400 moves or else you could get beaten by a beginner (like me) that chooses to do 2/2 and does it correctly in 29:59.99.

that's what I don't understand...

if someone goes for, say, 10 cubes, and finish 9, why should someone who did 2/2 win???

 

[joey]

that's what I don't understand...

if someone goes for, say, 10 cubes, and finish 9, why should someone who did 2/2 win???

100% perecent accuracy?

Is 2/2 better than 9/10? Yes because of accuracy, but the 9/10 person still got 9 cubes solved.

 

[Erik]

then I could ask for 1000 cubes and pick the 10 easiest and forget about the rest