What do I learn next?

[zigzagchris]

I curently average around 1:20 I am only 13 but i dont know what to learn next to get faster. I use f2L and the beginers other half. I don't have the time to learn oll and pll so is there any thing i should learn first.

 

[Kristoffer Absalonsen]

f2l can be done in less than 10 seconds, so it can be done much improvement there

 

[chue.hsien]

f2l is the most important part of fridrich in my opinion. i cant sub-20 if i screw up on f2l. pll and oll can come later, when u average around 30+

 

[badmephisto]

you dont need *time* to learn OLL/PLL per se. Don't be afraid of it, and just learn them one at a time as days go by. Don't set any goals, just have a printout of the algorithms next to your cube or something, and if you see some easy cases that you see are occurring frequently, then just give it a shot... my point is, don't be afraid of it! There is like 20 cases in OLL's that are like really trivial anyway, and can be memorized very easily too.

i learned around 20 OLL cases in a month and I was barely trying... Also, I find that they become easier to learn the more and more you already know.

 

[robertpauljr]

How often do you practice and how many solves do you do each day? How long have you been cubing. Read Cube Nirvana

 

[clincher]

no offense but your schedule is pretty full when you're 13. You have time.
Life is simple people complicate it

 

[AvGalen]

With practise and lookahead you can get sub-20 if you know F2L and 4 look last layer. You only need OLL+PLL to get extremely fast.

 

[zigzagchris]

is 4 look the last four steps the solution guide it comes with?
Thanks for the help I am learning pll and oll exept for oll i do a cross first so i dont need to learn so many oll algs

 

[Lotsofsloths]

Hello, zigzagchris!
I'm 12 years old, and yea, I can solve it, I average around high 30s.
But I use the edges then corners when doing the OLL, as for the PLL, I used to do the edges then the corners, but now I am trying to learn all of them
Goto cubewhiz.com, for the PLLs, they have awesome algs that fit my tiny hands lol!

As for 4 look, i think it means you use your index find to quickly twist the top last layer 4 times around, looking at all the sides quickly and preforming the correct PLL.

By the way...i joined your forum

 

[Jack]

As for 4 look, i think it means you use your index find to quickly twist the top last layer 4 times around, looking at all the sides quickly and preforming the correct PLL.

Actually, a 4 look means that you can solve the full LL in 4 looks (1st is EO, 2nd CO, 3rd CP, 4th EP) assuming you solve in that order of course. So full Fridrich would be a 2 look.

 

[TimMc]

Actually, a 4 look means that you can solve the full LL in 4 looks (1st is EO, 2nd CO, 3rd CP, 4th EP) assuming you solve in that order of course. So full Fridrich would be a 2 look.

Lol, I guess I'm always doing CFOP with 4LL then

...except when I skip something in LL

Average has gone up to 45 seconds x.x

I seem to find that I can solve it faster in public when I'm on a train or something than when I'm sitting at my desk. Although, I've never got a timer handy on a train... but Cross and F2L recognition definitely seem faster :-/

 

[Johannes91]

I guess I'm always doing CFOP with 4LL then

CFOP is 2-look LL by definition...

O = OLL
P = PLL

If your LL is something different, then you're not using CFOP.

 

[MAHTI-ANSSI]

Johannes, your exactness is boring..

 

[TimMc]

I guess I'm always doing CFOP with 4LL then

CFOP is 2-look LL by definition...

O = OLL
P = PLL

If your LL is something different, then you're not using CFOP.

Well I did say CFOP with 4LL, kinda implied that it's not the same as CFOP

 

[h3ndrik]

I guess I'm always doing CFOP with 4LL then

CFOP is 2-look LL by definition...

i disagree. it stands for cross - first two layers - orient last layer - permute last layer. nothing said about doing for example orienting last layer in one _single_ step.

 

[Johannes91]

CFOP is 2-look LL by definition...

i disagree.
nothing said about doing for example orienting last layer in one _single_ step.

I thought that OLL and PLL refer to the steps in Fridrich (57 and 21 cases, respectively). So I wouldn't say that somebody who knows a typical 4-look LL knows OLL and PLL.

 

[Johannes91]

Johannes, your exactness is boring..

But everybody's inexactness is annoying...

Well I did say CFOP with 4LL, kinda implied that it's not the same as CFOP

Also, there are three L's in "4-look LL" so I think you should say 4LLL.

 

[h3ndrik]

who said that someone who knows a 4 look LL knows OLL? with a 4 look LL in pure form he would only know 10 out of 57 OLL algorithms.
I see OLL being a stage of a fridrich solve, not a specific set of algorithms. if you do eo & co after f2l you have just oriented the last layer, therefore Oriented the Last Layer.

EDIT: ok, next time i have to QFT every of your posts i refer to, johannes91.

 

[Johannes91]

if you do eo & co after f2l you have just oriented the last layer, therefore Oriented the Last Layer.

I guess I've more or less misunderstood what CFOP means because I thought it's basically pure Fridrich.

Would a basic LBL be CFOP, too? The 'F2L'-stage is just done differently.

EDIT: ok, next time i have to QFT every of your posts i refer to, johannes91.

What do you mean? I don't think I did any big edits. But yes, quoting is a good idea.

 

[h3ndrik]

if you do eo & co after f2l you have just oriented the last layer, therefore Oriented the Last Layer.

I guess I've more or less misunderstood what CFOP means because I thought it's basically pure Fridrich.

Would a basic LBL be CFOP, too? The 'F2L'-stage is just done differently.

i think of cfop as an acronym for the steps you are doing to solve the cube.
the layer by layer method also works like cross - first 2 layers - orient last layer - permute last layer. I'd say yes, because in cfop you are actually solving the cube Layer by Layer. its basically the same, but fridrich-cfop is more sophisticated