What constitutes a lucky solve?

[masterofthebass]

And I judged one of Eriks other solves at the Dutch Open. He finished F2L, waited a second before starting his regular OLL and than did a 1 look last layer instead by using a different method for the last layer (time: 13.10). How would a judge ever rule if that was lucky or not without knowing Erik personally like I do?

That's exactly my point. There won't a time where a solve doesn't count, if the cube is actually solved.

 

[Pedro]

Most judges at competitions have enough trouble recognizing a good solve and a +2 solve. At worlds, some people got DNF-ed after a +2 solve

were there more people? I tought I was the only one

 

[joey]

Yes, I kknow there was a girl who this happened to (Polish I think)

 

[Stefan]

At worlds, some people got DNF-ed after a +2 solve

And they didn't correct the judge?

 

[Pedro]

At worlds, some people got DNF-ed after a +2 solve

And they didn't correct the judge?

no yeah...I should know the rules

 

[Jack]

I have a question about +2 on the 5x5, at the Canadian Open I got a DNF for a 5x5 solve where one slice was turned (for example the r slice), would this count as a +2 or DNF? Not that the solve was any good anyway, back then I averaged 5:30 on the 5x5.

 

[masterofthebass]

It's considered a DNF. I hate that rule, but because the +2 is done by HTM, it counts as a DNF. You need to do 2 moves to get it solved, just like having an M slice off on the 3x3. At least, that is my understanding of the rule. I think that it's stupid, but o well, what can you do.

 

[ExoCorsair]

If it is just 1 layer, then it is a +2.

If it is more than 1 layer, then it is a DNF.

See Takayuki Ookusa's WR solve to see an example of a +2.

 

[amateurguy]

OK.....stepping aside from +2 penalties....I think I understand lucky solves now. It all depends on the method. The weird thing is (which is actually quite morally reasonable) the more you learn, the less chance you'll get a lucky solve.

And to some people who posted somewhere up there, I know that lucky solves are still counted in competitions and are not really important. But at home I have to know whether it was lucky or not to ensure I don't overestimate myself. If I get 40s solves (lucky ones but I don't know that they are), I might go 'Yes! I can average sub-50 now!'. Then I try again when I'm not lucky and I'll be hitting around 55s. It sorts of decreases my morale if that happens (But getting a 40s non-lucky solve would 'up' mine! ) Like AvGalen said, I don't want to use lucky times as an indication of my skill.

Thank you everyone!

Oh, a few last questions: I vaguely remember skipping one F2L pair is counted a lucky skip. True or not? And if the F2L pair is ALREADY matched up and can be inserted with a 3-move trigger (e.g. RU'R'), does it count as a skip (because I got a REALLY fast time due to the automatic matching of 3 F2L pairs one after the other, without skips in my 4LLL)?

 

[AvGalen]

About the +2 penalty: http://www.worldcubeassociation.org/regulations/#solvedstate
10e2) If one or more adjacent slices do not comply to regulation 10f, then the cube is considered solved, with a penalty of 2 seconds

Example: On a 5x5x5 all 5 horizontal layers can be a quarter-turn away from the one under it and also a quarter-turn away from the one above it and it will still be a +2.

Example2: On a 4x4x4 all 4 horizontal layers can have a different color and it will still be a +2.

Example 3: On a 3x3x3 M2 away from solved will give you a +2.

 

[Pedro]

About the +2 penalty: http://www.worldcubeassociation.org/regulations/#solvedstate
10e2) If one or more adjacent slices do not comply to regulation 10f, then the cube is considered solved, with a penalty of 2 seconds

Example: On a 5x5x5 all 5 horizontal layers can be a quarter-turn away from the one under it and also a quarter-turn away from the one above it and it will still be a +2.

Example2: On a 4x4x4 all 4 horizontal layers can have a different color and it will still be a +2.

Example 3: On a 3x3x3 M2 away from solved will give you a +2.

hmm...so M' or M2 is just a penalty? nice to know

 

[tim]

About the +2 penalty: http://www.worldcubeassociation.org/regulations/#solvedstate
10e2) If one or more adjacent slices do not comply to regulation 10f, then the cube is considered solved, with a penalty of 2 seconds

Example: On a 5x5x5 all 5 horizontal layers can be a quarter-turn away from the one under it and also a quarter-turn away from the one above it and it will still be a +2.

Example2: On a 4x4x4 all 4 horizontal layers can have a different color and it will still be a +2.

Example 3: On a 3x3x3 M2 away from solved will give you a +2.

hmm...so M' or M2 is just a penalty? nice to know

o_O i thought M2/M would be a DNF, because two slices are away from solved state (compared to each other). But that's really nice to know. So i don't have to worry about the state of my M slice at the end of my BLD solves.

 

[masterofthebass]

Yeah, wow. I really thought those were DNFs as well. So Jack, apparently you're solve was legititamite. That's really nice to know for big cubes.

 

[adragast]

Do you know if this is also true for blindfold solve ?

 

[AvGalen]

Short answer: Yes

Detailed answer:

http://www.worldcubeassociation.org/regulations/#blindfoldedsolving

B1)Standard procedure is followed as described in Article A (Speed Solving).
Additional/special regulations for Blindfolded Solving are described below.

And none of the additional/special regulations describe penalty or DNF, so the rules are the same.