D
Deleted member 27249
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I think this:
F2L
Solve four Last corners
Oriented eight Last Edges
Solve eight Last Edges
F2L
Solve four Last corners
Oriented eight Last Edges
Solve eight Last Edges
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if you do F2L, arent there only 4 edges left?I think this:
F2L
Solve four Last corners
Oriented eight Last Edges
Solve eight Last Edges
No because i dont create cross.if you do F2L, arent there only 4 edges left?
Isn't that pretty much the Friedrich Method?
if you do F2L, arent there only 4 edges left?
Isn't that pretty much the Friedrich Method?
Solved First 4 corners and belt.if you do F2L, arent there only 4 edges left?
Isn't that pretty much the Friedrich Method?
To me that seems pretty inefficient (U, D, M, S at the end of the solve). Are there any benefits for speedsolving?Solved First 4 corners and belt.
After solve Last 4 corners.
There are 8 Edges dont solve.
It was an idea that suddenly formed.To me that seems pretty inefficient (U, D, M, S at the end of the solve). Are there any benefits for speedsolving?
Ah ok.Not a new idea
My question would be how feasible is it to one-look 10 pieces. That seems too wild to be possible.LMCF-H solves all the corners and the FL and BL edges (an 'H' or columns on the left half of the cube), all in 1-look. What remains is a single opposite edge pair in the R slice and you have reached full columns in 2 looks. After which one more edge pair is solved, and you finish with L6E, which is a somewhat more expanded L6E set than Roux because it allows for the two remaining unsolved L/R edges to be UR/DR or UL/DL.
Columns has promise, the problem is the speed & number of looks to reach full columns. Once you are there the rest is fast.