Thankscubing Day Competition - Nov. 21, Columbus, Ohio, USA

JBCM627

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Thankscubing Day Competition!
Nov. 21 (the weekend before thanksgiving) - Ohio State University

http://www.cubingusa.com/thankscubing/
Mystery events include pie-ing Bob Burton if he comes.
Unofficial events include lunch and dinner.

This competition will also have a unique aspect to it - teams. Competitors will be evenly divided into two groups, and scored. The winning team will win prizes tbd. A preliminary list of teams should be announced sometime the week before the competition, but may change depending on how many people and who registers late.
 
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Oh no, I probably can't go because of the date. I know many other cubers also will probably spend this time with their families. If only it was on Friday.....
 
Oh no, I probably can't go because of the date. I know many other cubers also will probably spend this time with their families. If only it was on Friday.....
It is the weekend before thanksgiving, not thanksgiving day. This is before the usual thanksgiving break, so many people probably won't have traveled yet.
 
This competition will also have a unique aspect to it - teams. Competitors will be evenly divided into two groups, and scored.

Are you going to do that arbitrarily or based on some kind of stats?

It is a somewhat interesting CS problem to optimize teams and make them as even as possible - this is ideally what we would do. If a competitor hasn't competed before, they would need to be randomly assigned, perhaps weighted by the number of events they are doing.

So it is arbitrary to a point, but we will probably write some sort of code to try and make them even. Competitors who don't pre-register probably won't be assigned to a team.
 
This competition will also have a unique aspect to it - teams. Competitors will be evenly divided into two groups, and scored.

Are you going to do that arbitrarily or based on some kind of stats?

It is a somewhat interesting CS problem to optimize teams and make them as even as possible - this is ideally what we would do. If a competitor hasn't competed before, they would need to be randomly assigned, perhaps weighted by the number of events they are doing.

So it is arbitrary to a point, but we will probably write some sort of code to try and make them even. Competitors who don't pre-register probably won't be assigned to a team.

Sounds cool. Good luck with that, I'm interested in seeing the results.
 
This competition will also have a unique aspect to it - teams. Competitors will be evenly divided into two groups, and scored.

Are you going to do that arbitrarily or based on some kind of stats?

It is a somewhat interesting CS problem to optimize teams and make them as even as possible - this is ideally what we would do. If a competitor hasn't competed before, they would need to be randomly assigned, perhaps weighted by the number of events they are doing.

So it is arbitrary to a point, but we will probably write some sort of code to try and make them even. Competitors who don't pre-register probably won't be assigned to a team.

Sounds cool. Good luck with that, I'm interested in seeing the results.

I hope I can go!
 
Another question about the teams, advancement to the next round is still based on individual performance, right?

I just think some people might worry about being on the wrong team, but I'm guessing it's solely for the prize, nothing else.
 
Bryan: It's still an official WCA-competition. So all rules must be followed and the competition will be run like any other?

There's actually no official rules about who advances in a round. I could say that the second round consists of the top competitor named "Bryan" and the top 15 non-Bryan competitors, and that still follows the regulations.
 
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