Super super mega PLL challenge that you probably won't care about

applemobile

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Just for fun/the love an respect of all.

One must perform 5 PLL's in a row and time it. That simple.

Rules.

Cube must start in a solved state.
Cube must end in a solved state.
AUF all you want.
All 5 PLL's must be different. (e.g all 4 G-perms count as DIFFERENT PLL's)

Video responses prefered.
 
Sorry, no camera to take video, but I did 7.16 with A, A, U, U, H. I'm pretty slow, though.

Edit: Wait, that was the same U twice, just from the opposite angle. best I can do is 8.69 with AAUUZ.
 
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Just so I'm sure, this is possible, yeah?
yes. He allows any amount of auf, so you can do any 4 random PLLs, and then do whichever fifth one will solve it

I think what he meant was whether or not you would get one of the PLL's that you had used before? Actually, I think that if you do 4 random PLL's, you are less likely to get a PLL that you have used before then you are to get one that you have already used.
 
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