How do you do commutators on a Square-1? How can you create an intersection of A and B of just one piece/block?I used to use this method before I learnt Vandenbergh! The coolest part is probably that you can do 4b using 3-cycle commutators, so the whole solve requires zero algorithms. (Fun fact: when I did this, I used slice moves on both the left and the right, which looked pretty weird to a classmate who was an experienced squanner.)
(Notation: R = /; L = y2 / y2; U = (2, 0); D = (0, 2).) [D' L D, R] is a 3-cycle. If you expand and rewrite it to use only normal slices, it becomes D' / U / U' / D /.How do you do commutators on a Square-1? How can you create an intersection of A and B of just one piece/block?
|Thread starter||Similar threads||Forum||Replies||Date|
|Speedy Square-1 Solving||General Speedcubing Discussion||4|
|Some Square 1 solves||Puzzle Video Gallery||0|
|M||[Member Intro] I like to do square 1||Member Introductions||7|
|XMan Volt v2 Square-1 Setup Timelapse!||Puzzle Video Gallery||0|
|Square One Scallop Kite Cubeshape Tutorial||General Speedcubing Discussion||0|