Simple Little Idea for Higher-order Cube Edge Pairing

You cannot preserve the eight edges, you wont be able to do certain moves as they would put the edges in the way of making the centers.
You could make 6 edge pairs instead to allow some freedom, but not eight. This could be a good method, it just needs some tweaking.
 
You cannot preserve the eight edges, you wont be able to do certain moves as they would put the edges in the way of making the centers.
You could make 6 edge pairs instead to allow some freedom, but not eight. This could be a good method, it just needs some tweaking.

He edited his post, explaining that 6 tredges would be preserved. Then he would solve the last 6 tredges and 6 centers. Like I've previously stated, I'll stick with Stadler/KBCM.
 
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