Scrambling just one layer for practice

[scorpiuss]

Hi, pardon me if this question is a very basic question or something, I've Googled and searched some threads here and there before but couldn't find anything related.
So I'm new to Rubik's cube, right now solving 3x3x3 under one and a half minutes.
and know how to solve 2x2x2 and pyraminx but my question is
How scrambling just one layer for practice and simulate some kind of situations(e.g. Yellow layer) so then I can practice things like parity errors in 4x4x4 and etc.(right now my question is related to 4x4x4)
Thanks for reading my question.

 

[PurpleBanana]

Use last layer scrambles on qqtimer.net.

 

[scorpiuss]

Thanks for reply.
But I don't think that will work, It says 'get last scramble' and that causes to load last scramble alg not last layer one.

 

[PurpleBanana]

You have to choose the correct option from the dropdown menu on the upper left.

 

[scorpiuss]

Thanks.
But that's not it I guess.

 

[PurpleBanana]

What do you mean by that?

 

[scorpiuss]

If you mean that blue link in front of algorithm and hypothetically I have chosen the right options
then clicking 'get last scramble' will give me the last scramble, in this case that is nothing like the
second screenshot I have uploaded.
I just want to scramble the yellow layer of a 4x4x4 cube for practicing reason to solve
last layer over and over again, specially ERROR situations, and not going to solve it entirely from scratch every time.
Thanks again for replying.

 

[PurpleBanana]

There is no feature to scramble the last layer of a 4x4 which will give you parity cases. There is a feature to scramble the last layer of a 3x3, and you can use that feature on the 4x4 last layer, but it will not give you parity errors.

 

[TheFearlessPro]

You can just do the parity alg over and over?

 

[PurpleBanana]

You can just do the parity alg over and over?

I'm assuming he wants to practice recognizing whether he has parity or not. This is obviously very easy for OLL, but for PLL it may be somewhat harder to figure out if you have a normal PLL case or not.

 

[TheFearlessPro]

I'm assuming he wants to practice recognizing whether he has parity or not. This is obviously very easy for OLL, but for PLL it may be somewhat harder to figure out if you have a normal PLL case or not.

lol well I guess you can set it up using the alg and see what it looks like xD true doe, I think cstimer might have options

 

[PurpleBanana]

lol well I guess you can set it up using the alg and see what it looks like xD true doe, I think cstimer might have options

I checked cstimer. I don't think there is a 4x4 LL option.

 

[scorpiuss]

There is no feature to scramble the last layer of a 4x4 which will give you parity cases. There is a feature to scramble the last layer of a 3x3, and you can use that feature on the 4x4 last layer, but it will not give you parity errors.

That's good too, may you please explain that, where can I get that at least?
Thanks again.

 

[scorpiuss]

Thank you PurpleBanana for your replies, one more question.
Is there any non-3x3 type solving Rubik's Revenge that you know?
If there is, please give me some useful links/tutorials for that.:rolleyes:
That would be greatly appreciated

 

[ryanj92]

That's good too, may you please explain that, where can I get that at least?
Thanks again.

from this drop down menu:
https://gyazo.com/62dbda1c6928ed14092be6e7ee3eb264

select 3x3x3 subsets:
https://gyazo.com/3107b5be0003fe3c1c4d8644270931f2

then from the other drop down menu, select last layer:
https://gyazo.com/88864107c1437f566c471498d6aa6cc9

hope this helps!

As for 'non-3x3 type solving Rubik's Revenge' do you mean a method that doesn't have a 3x3 solving stage? The most common method of this type is called K4 and is documented here: http://snk.digibase.ca/k4/

 

[PurpleBanana]

That's good too, may you please explain that, where can I get that at least?
Thanks again.

Yes, you can go into qqtimer and go to 3x3 subsets, and then find the last layer option.

 

[scorpiuss]

Thank you guys very much.
@ryanj92, Yes that's what I mean, thanks for your help!
@PurpleBanana, thanks again for all your replies and helps.