PLL probabilities following OLL?

[No NWO]

I'm new and have searched this site for hours in addition to google trying to find an answer to my question...

Of the 57 OLL's - are their probabilities spelling out which PLL will follow? E.g. I have found that certain PLL's seem to always (or almost always) follow certain OLL's.

Much appreciation on any help anyone can give!

Thanks!!!!

 

[ben1996123]

no. at least I don't think so anyway.

 

[5BLD]

PLL probabilities following OLL

Prove that certain OLLs go to certain PLLs more often independent of the normal PLL chances please, am doubtful

 

[Cool Frog]

Chances of each PLL alone...

However some OLL>PLL cases might be a tad different (Don't know for certain)

Spoiler

A(a) 1/18
A(b) 1/18
U(a) 1/18
U(b) 1/18
H 1/72
T 1/18
J(a) 1/18
J(b) 1/18
Y 1/18
R(a) 1/18
R(b) 1/18
V 1/18
F 1/18
G(a) 1/18
G(b) 1/18
G(c) 1/18
G(d) 1/18
Z 1/36
E 1/36
N(a) 1/72
N(b) 1/72

 

[No NWO]

How will I be notified when my q is answered? God bless and XOXOXO!!!

 

[vd]

Its totally random which PLL follows which OLL, but I guess you did at most thousands of solves, and that is not big enough sample.

 

[No NWO]

Yup - I knew this one just thought these numbers were taken in vacuum. Was wondering if odds might vary depending on which OLL you get. I think my q was answered though and the answer is "no". Thanks everyone!!!

 

[ThomasJE]

I think not. Because the permutation of the pieces are random (as far as we can tell), and each OLL cycles the pieces. So let's say that before OLL, the pieces are in an A perm position. If the OLL does a U perm, you end up with a G perm. If it was solved before, you end up with a U perm. And with a H perm before, you end up with a U perm. And if you worked that out, you would end up with the same chances. If someone actually did this for all PLL's and AUF's (72 in total), that would be very interesting.

 

[Endgame]

In order to derive the permutation of pieces you could look at ZBLL cases, but then again they only cover "OCLL".

 

[cuBerBruce]

The standard probabilities assume you ignore the permutation of the LL pieces until the PLL step.

But if you know more than one alg for a given OLL case, and you are aware of how they affect the permutation, you could choose which one you use to influence what PLL case you will get. But you would need to incorporate knowledge of how the pieces are permuted while you are also recognizing the OLL case and choosing how to solve that OLL. You can also take advantage of symmetry for certain OLL cases.

For example, for OLL #57 in the Wiki, you could rotate the cube 180 degrees (or just the U layer, of course) and still use the same alg. If your alg affects the permutation of the pieces then, you may get two different PLLs just by choosing which angle you use. You could also consider mirroring the alg since this OLL case is also mirror-symmetric. This makes it possible to get four different PLL cases.