Odd parity Algorithms (specifically, single edge "flip")

I will repeat my self.

I dont care if this alg is suitable for speedcubing, Im just interested in understanding some theory about the parity algs.

So I would still like to see those algs you have found.

Henrik
 
qqwref said:
cmowla said:
And for those who don't believe me, I completely understand...I can hardly believe it myself[/I]
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This is exactly what peer review is for :)

SiGN is the best notation to use (in my opinion) for algorithms involving various weird block turns. The basic way it works is:
- turns of only layer 1, 2, 3, etc. are R, 2R, 3R, ...
- turns of layers 1-2, 1-3, etc are r, 3r, ...
- turns of layers A-B are A-Br (for instance you can use 2-3r as a replacement for an M' move on the 4x4) - this doesn't HAVE to be used but it's far less ambiguous than the normal slice turns and probably easier to understand too.
Click to expand...

+1.

Here is a pictorial representation of SiGN that was perpetrated by the usual suspects:

http://twistypuzzles.com/forum/viewtopic.php?p=121194#p121194
 
I just found a 13 BQTM alg for a pure edge flip but I won't tell anyone because I'm going to make a book about it and become a millionaire.

But seriously, erm what is the reason you aren't posting your algorithm?
If you were to publish a book on it, I highly doubt any more than 10 people would buy it...

Oh yeah, you can't just publish a book with a click of your fingers. There needs to be a market for it. I doubt people would walk into a book store, and buy it.

Well, the book was just a lmao idea.

What's the reason? Because right now, I don't think many people believe you at all.
 
ChrisBird said:
My guess is that he hasn't found one and just wants us to think he is smart.
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My guess is that he's found one, but he's just not ready to share it.
I'm pretty sure he can count the number of moves correctly, and I don't think he would lie about something like that. Neither do I think he's going to pull a Stieltjes on us.

Meanwhile, I'm perfectly content going on without knowing it for now. It just means there's more interesting stuff out there.
 
I have now found a 21 BQTM algorithm which gets rid of OLL parity from a scrambled "3X3X3" state on the 4X4X4.

Thus, the alg is not a pure one, but is does break the odd permutation and reunites all centers and edges in just 21q.

This is not a double parity alg.
 
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nlCuber22 said:
cmowla said:
I have now found a 21 BQTM algorithm which gets rid of OLL parity from a scrambled "3X3X3" state.
Click to expand...
Click to expand...
nlCuber22 said:
cmowla said:
Thus, the alg is not a pure one, but is does break the odd permutation and reunites all centers and edges in just 21q.

This is not a double parity alg.
Click to expand...

fazrulz said:
cos he's very lmao
Click to expand...

yeah
Click to expand...

Believe me now?

r U2 r' U2 r D2 r D2 r' F L' F' U' r' D2 r

or in single slice turns:
r U2 r' U2 r D2 r D2 r' F L' F' U' r' D2 r

I have decided to show this alg to let everyone know that none of this is a joke (since you couldn't take my word for it before). Believe what Lucas Garron says, because he couldn't be more right.

And all who give this alg to others (to use for any purpose), give me credit. I found it by hand, and it is officially (because the public has seen it) the briefest algorithm to break only OLL parity (with edge and center preservation). In actuality, my 20 BQTM pure edge flip is more briefer to solely break OLL parity (not double parity, that's 19 BQTM--I have found 3 of those by hand too), but I haven't released it yet for it to be officially the most optimal. "Come on, a pure algorithm is more optimal than a non-pure?" YES, at least in this case, as far as my findings have said.

On the contrary, for the digaonal swap of individual winged-edge pieces, my non-pure 17q (which swaps the top-front-left winged edge with the top-back-right winged edge):
r U2 r U2 r2 U2 r x2 U2 l F2 r' x'
is 2 BQTM shorter than my pure diagonal swap (which is 19 BQTM).


Date: 1/9/10
 
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This is cool, thanks :D funny alg, even though I dont know if I vile ever use it.

Did you say you had found a pure alg in 20 BQTM?
Can we see that one too. I think its cool you found these by hand.
 
Henrik said:
Did you say you had found a pure alg in 20 BQTM?
Can we see that one too. I think its cool you found these by hand.
Click to expand...

Yes. And not right now. Yes, I think it's cool too. I actually like finding the briefest algorithms in the world by hand for fun. I never was interested in using computers (and I never learned how to use them either, although I wrote a TI-83 plus calculator program that pairs up the last layer edges k4 style).
 
I now found a 19 BQTM pure edge flip algorithm for the 4X4X4 and only for the 4X4X4 (or even cubes treated as a 4X4X4, where it appears the entire composite edge needs to be flipped).

I used the same method that I used to find the 20 BQTM.

This alg is even more ugly than the 20 BQTM pure edge flip alg because it doesn't contain anymore half turn moves (it is composed only of block quarter turn moves).

Hence, it's 19 BQTM/19 BHTM.

Another interesting thing is that it is still 26 qtm in cube twister (if you have been reading this entire thread, you will notice that I mentioned before that I could not achieve less than 26 qtm with any of the other algs which I have previously found). Interesting.

For all who doubt me, don't worry because I will actually consider releasing these algs (my 24's, 23's, 22's, 20, and 19) to the public in the near future. I highly doubt it will be for a price. Instead it will just be a documentation of some kind where I give a plausible derivation (which will be pretty long, especially for the 19 and 20 BQTMs) for each (and where I can clearly get officially credited for these algs and the process to find them...anyone who uses my methods cannot get credit for any algs found from them without mentioning my name as well as theirs). In addition, I will be in favor of people displaying the algs I have found on Youtube, on their website(s), or anywhere as long as I am given credit (that includes not crediting computer solvers, which I did not use to find these algs).

Any suggestions on how I can do officially establish my credit is welcomed. But please, keep it to a minimum in this thread, for that is not puzzle theory (pm me if you can).

1/12/10 6:43pm central time USA
 
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cmowla said:
Henrik said:
Did you say you had found a pure alg in 20 BQTM?
Can we see that one too. I think its cool you found these by hand.
Click to expand...

Yes. And not right now. Yes, I think it's cool too. I actually like finding the briefest algorithms in the world by hand for fun. I never was interested in using computers (and I never learned how to use them either, although I wrote a TI-83 plus calculator program that pairs up the last layer edges k4 style).
Click to expand...

Could you share the code?
 
fanwuq said:
Could you share the code?
Click to expand...

Sure. Just give pm me your email and I will send you the application (which you can use Ti-connect to download it to your calc). I will also send you a pdf explaining how to input the positions of winged edges of your cube. Note: You need to have solved the LL corners first, just like k4. Then, you can use it to solve the LL winged edges for every set of complimentary winged edges, e.g., the 7X7X7 cube, etc, but you must solve one complimentary set at a time).

Once you input the information (which is very easy), it will give you all the moves (in several steps, just like k4...commutators--ones that I have come up with..and the 2 cycles are common ones which you have seen before) to solve the cube. Follow the moves exactly (including cube rotations). These moves are not necessarily the most efficient to solve the cube. Instead, it comes very close to how humans solve the LL edges. Like Thom Barlow said in his guide, it takes about 3 algorithms to solve the LL edges...this program does it at most 4 different algorithms (most of the time, it puts in two pieces at a time..and if the solve permits, 3 at a time). It solves the winged edges primarily with 3 cycles, and, if there is parity, then the last algorithm is a 2 cycle (which can be any of the forms of odd parity that comes with the solve).

The notation is the regular notation from Chris Hardwicks 4X4X4 solution page.
 
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cmowla said:
clearly get officially credited for these algs and the process to find them...anyone who uses my methods cannot get credit for any algs found from them without mentioning my name as well as theirs). In addition, I will be in favor of people displaying the algs I have found on Youtube, on their website(s), or anywhere as long as I am given credit
Click to expand...
Looks like I'm not gonna read your stuff, as I want nothing to do with that kind of mentality...
 
cmowla said:
I wrote a TI-83 plus calculator program that pairs up the last layer edges k4 style
Click to expand...

Maybe your wording is incorrect, but you don't pair edges on the K4 last layer.

cmowla said:
Instead, it comes very close to how humans solve the LL edges. Like Thom Barlow said in his guide, it takes about 3 algorithms to solve the LL edges...this program does it at most 4 different algorithms (most of the time, it puts in two pieces at a time..and if the solve permits, 3 at a time).
Click to expand...

The maximum (not average) number of algorithms should be three.
 
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