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New Method

BillT

Member
Joined
Mar 20, 2006
Messages
23
Location
Reading, PA, USA
When I first started cubing, I thought it would be cool to create my own method. I did, but quickly decided it wasn't worth working on. Well, recently I started thinking about this method, and wondered what other cubers would think of this method. It consists of six steps, create a 2x2x2 block, add 3 2x2x1 blocks (I counted this as three steps), solve a corner/edge pair, and solve the remaining five pieces.

First 2x2x2 Block:
Pretty self explanatory. Just build a 2x2x2 block:

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Adding 2x2x1 Blocks:
Add a 2x2x1 block to each side of the 2x2x2 block:

100.png

100.png

100.png


Solve a Corner/Edge Pair:
Pick one the the three slots and solve the corner/edge pair.

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Solve the remaining five pieces:
This will consist of, at max, 83 algorithms.

100.png


So, let me know what you think. I really don't know if this is worth developing, but I'd just wanted to share my idea. ;)

-Bill
 
Bill,

I tried this method a while back and there are some good and bad things about it. The "1-look" finish is seems extraordinary, but I'm not sure it's worth it. Let's compare:

Fridrichs Other
= Cross + 3c/e pairs = <Pseudo Cross+3c/e pairs>
+ 4th pair - <2x2x1 block>
= OLL = <insert 4th pair while preserving block>
+ PLL - <Orient/Permute All>

The 2x2x1 block in the LL is sometimes a real pain to set up. Sometimes it's easy though. As far as inserting the 4th pair while preserving the 2x2x1 block, I never came across a consistent way to do this inuitively. Let me know if you have. My verdict here is that this method would not work by itself, but if used in appropriate situations it could be fast. The LL cases will always be useful just because they can be applied when they happen randomly during a fridrichs solve.

my 2 cents
-Richard
 
For inserting the 4th pair, I have one alg that I use to do this: R' F R F'. This alg can be reflected over the UF, UR, and FR edges and rotated around the URF corner. For the majority of solves, this needs to be use a maximum of three times, as long as you try to be color independent and look at all three slots. There are a few cases where you need it four times though. As for the last 2x2x1 block, I alway find this fairly simple. My pb time with this method is 27.8x. By the way, I also figured out a name for this method: the B.I.L.L. method. :D Build first four blocks, Insert corner/edge pair, and Last Layer solve. :P

-Bill
 
Bill,

I'd be interested in seeing the optimal sequences for inserting the 4th pair+preserve 2x2x1 block. Also, I have a table made up for all the last layer cases that occur if you're interested. let me know --
 
Heres the algs for the LL.

http://www.ws.binghamton.edu/fridrich/L1/ece.htm

They're set up to be solved on the F layer though :blink:
also reflections and symmetrys arent present.

The only problem with this method is creating that last 2x2x1 quickly...

For the last f2l pair, I'm thinking about generating the algs to pair up, insert, and orient the LL edges, Not too many to learn, and you'd avoid the worst LL cases.
 
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