My method for centers on 6x6x6 and 7x7x7

[Parity]

Ok I am not sure if this is a way someone already made but I did this on my own.

First:I get the inner centers.

Second:I build 2 1x2 blocks and place them directly opposite of each other.

Third:I make 2 1x4 blocks and place them on the last 2 remaining sides.

This does not work on last 2 centers.

 

[waffle=ijm]

i do this...
I find it easier than making columns...

 

[Parity]

i do this...
I find it easier than making columns...

I do to.
I use it on 7x7x7 because it is easier for me to find the center edge pieces.

 

[Daniel Wu]

I do the same thing as well.

 

[Zaxef]

DIS IZ SO NEW

 

[qqwref]

Frank Morris does this (or did at the Essen competition, anyway).

You can do this on the last two centers if you "pair up" the obliques. What I mean is, solve the two 2x2 blocks, then pair up all of the obliques so that you have essentially reduced the last two centers to the last two centers of a 5x5. Then you can solve from there without any commutators. This is probably less efficient than the normal way, but it may be easier for you.

 

[trying-to-speedcube...]

Frank Morris does this (or did at the Essen competition, anyway).

You can do this on the last two centers if you "pair up" the obliques. What I mean is, solve the two 2x2 blocks, then pair up all of the obliques so that you have essentially reduced the last two centers to the last two centers of a 5x5. Then you can solve from there without any commutators. This is probably less efficient than the normal way, but it may be easier for you.

I use that method for the last 2 centers. I'm pretty decent at it, I think. Most of the time, after you paired the "4x4" centers, about 4/8 oblique pairs are already paired up. You can pair 2 at a time with an easy setup, 3R 2R' U 2R U' 3R'. For me it's faster than the "normal" method.

 

[Muesli]

I do the columns method. I quite like lines, but then again I'm not one to comment on big-cube speedcubing.

 

[Daniel Wu]

Frank Morris does this (or did at the Essen competition, anyway).

You can do this on the last two centers if you "pair up" the obliques. What I mean is, solve the two 2x2 blocks, then pair up all of the obliques so that you have essentially reduced the last two centers to the last two centers of a 5x5. Then you can solve from there without any commutators. This is probably less efficient than the normal way, but it may be easier for you.

I use that method for the last 2 centers. I'm pretty decent at it, I think. Most of the time, after you paired the "4x4" centers, about 4/8 oblique pairs are already paired up. You can pair 2 at a time with an easy setup, 3R 2R' U 2R U' 3R'. For me it's faster than the "normal" method.

Wow. That's amazing. I had never even thoght about that. I have so much to learn.

 

[Rubenx96]

cool that's awesome. but i rather go with columns