Mirror of an alg

[UKCubeFan]

I would love someone to help, if possible. This has 3 cases:
1 solved
2 this one
3 and the (mirror?) of 2 if that's the right term
What is alg for 3?
I know it has to be transposed some way or other.

F' L' U M2 U' L U M2 U' F

 

[Bingus Ringus McDingus]

I would love someone to help, if possible. This has 3 cases:
1 solved
2 this one
3 and the (mirror?) of 2 if that's the right term
What is alg for 3?
I know it has to be transposed some way or other.

F' L' U M2 U' L U M2 U' F

Well, the algorithm for 3 would be, if it's inverse:
F' U M2 U' L' U M2 U' L F

And for righty instead of lefty, it would be:
F R U' M2 U R' U' M2 U F'

 

[UKCubeFan]

Thanks? Do you know what's optimal for this similar ish case?

U2 F L2 D2 R2 B D F2 R2 D2 R2 F2 D2 R2 D' L2

Hope u or someone can help with this.

 

[Bingus Ringus McDingus]

Thanks? Do you know what's optimal for this similar ish case?

U2 F L2 D2 R2 B D F2 R2 D2 R2 F2 D2 R2 D' L2

Hope u or someone can help with this.

For this, I would hold the unsolved pieces on the top-right, not the top-left, and do this algorithm:
U R M2 U' M U2 M' U' M2 R' U'
Reminder, M is bringing the middle layer DOWN, not up. Bringing it up would be M'.

 

[UKCubeFan]

For this, I would hold the unsolved pieces on the top-right, not the top-left, and do this algorithm:
U R M2 U' M U2 M' U' M2 R' U'
Reminder, M is bringing the middle layer DOWN, not up. Bringing it up would be M'.

Much obliged. 11 and other one 10.

 

[UKCubeFan]

Actually my own original alg is 10 for the 11 one. I counted it as 14 as it has M & E moves e.g. L' R' is 1 move not 2.