Large average progression equations

[StachuK1992]

After a bit of punching buttons on my calculator, I've found that the following represents how my larger averages usually progress:

\( 14+ \tfrac {30}{sqrt(x)} \)

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[Tim Reynolds]

Wait, this means that, the more solves you do, the faster your average gets? If anything, the opposite would be true: once you do a lot of solves, you're probably getting tired. What data points did you use to compute this? What x are you saying this is a good approximation for?

Statistics needs disclaimers. You can't just do a regression and be like "this is true".

 

[StachuK1992]

Wait, this means that, the more solves you do, the faster your average gets? If anything, the opposite would be true: once you do a lot of solves, you're probably getting tired. What data points did you use to compute this? What x are you saying this is a good approximation for?

Statistics needs disclaimers. You can't just do a regression and be like "this is true".

This was meant to be a rough estimate, mainly for my first 100 solves.
Usually, I start off horridly, and get better, ending up at about 17s, getting 18s about halfway through.
After the first 100 solves, this becomes invalid.

After plenty solves, of course, my times would increase, but for me this is not true within my first ~100.