Intuitive SQ-1 solve?

antoinejobin

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Feb 20, 2010
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I'm about to get a Square-1 from PopBuying and I was wondering if it is solvable without the ''solution''.

I got my first megaminx lately, and I wanted to solve it all by myself without the help of a tutorial. I managed quite easily to do it since I noticed the similarity with the 3x3x3.

Is it possible to expect the same thing with the SQ-1? Can I take the bet of solving it all by myself? :p

The same question for my soon-to-be-received pyraminx.

(I have very good knowledge of the 2x2x2 to 5x5x5)

Thanks
 
I solved the Square 1 without help. I used the instructions to make it into a cube, then mixed it, then figured out tools to solve it. The parity problem threw me a bit, but I figured out a way to handle it. Today I still solve it my way, but with the exception of a faster parity fix algorithm that I found online.
 
Pyraminx should be easy to solve. I let someone try and solve it and they did. It took a little while though. They were a non cuber too. Square 1 on the other hand is more difficult. It was tough to get into a cube when I first got it.
 
Pyraminx is very easy, if you are stuck then use bob's lolmethod.

As for Square-1, I've got to cube shape intuitively and thats about all...Parity is definitely difficult to figure out.
 
...give it the time it deserves.
^^ good advice!

The fact that its quite different from 3x3 is more of a blessing than anything else. It really does feel like a 'new' puzzle.

I managed to solve all but the edges with fairly intuitive steps, then spent a good while figuring out algs to permute the edges. Most difficult is probably figuring out how do do an adjacent edge swap. Good luck :)
 
SORRY BUT YOU CAN'T! I guess so, but not to make a cube shape!(only) I am still learning to solve one, I can but memorising algorithms are left!
 
I have no idea what you are talking about :P

Solve the corners in the way one might solve the corners of a Rubik's Domino 3x3x2 puzzle. I suggest this as all the slice turns can only be 180 degree turns same as with a 3x3x2 or the more recent 3x3x4. It's quite intuitive.

I've also seen this described as an analogue of solving the last pair of centres of a 4x4x4. Try it and you'll see what I mean.
 
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