I use 15 algs but know 60, how 'bout you?

longshot789

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Nov 13, 2006
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I've found that If i ditch using special orient+perm algs I can perform much faster and much more consistently. I currently use 15 algs and I average 32.xx seconds. I'm wondering what other people's alg counts are and what their respective times are.
Now I understand that you reach a point with algorithms at which you can instantly recognize them and execute them, I wouldn't be at 30 seconds if i couldn't, but what I seem to be approaching is getting the actual effect on the cube faster(i.e. using a special alg) or being able to see ahead an alg or two and eliminating any hesitation or bogus AUF moves. Currently i'm faster when i can see ahead and not bother with the special alg.

BTW. I'm not counting F2L I figure once you can do those mirrored from any angle and with the cube sideways or whatever, its intuitive.
 
I am not sure exactly how many I know, but I use all of them whenever I get that case. The only way to get quicker with them is to practice them. Work on recognizing them, and then executing them, and you will improve.
 
I know all 57 oll and all 21 pll and know a few different ones for probably like 10 of those. Like PJK said, I do each and every one of them when they come up. It's the only way to get faster at recognizing them and seeing them.
 
Let's see. There's 57 + 21 basic ones. And then I probably know 5 different N perms (can't make up my mind...). I use 28 COLL algs...subtract 5 base, so that's 23 net. And then probably another 5 loose ones here and there. That's approximately 130 or so...
 
Not as many as some others. I know all 21 PLL, 10 OLL for 3-look LL and another random OLL that I learned from the Y-Perm PLL. So that's about 32.
 
I know a very limited amount of OLL algs but I know that my best times were those where the OLL case was one I recognized instead of doing 2 for the orientation stage. And I know all 21 PLL cases. Once I got quick at using the PLL cases my average dropped about 6 seconds because I only had to do one PLL instead of breaking it into 2 steps. I now average between 25 and 30, depending on whether I get an OLL case I recognize or not.
 
I realy know too many algs ;) I know all PLL's but for about half of them I know 2 or even 3 (Don't ask me why cause I only use 21 of them). I know about 49 OLL's, I 'll don't count special F2L cases... Also I know half of CLL cases so that's 20 more... I know the last steps of roux so that's another couple of algs. For non-3x3: +/- 5 megaminx algs. 3 4x4 algs. A whole bunch of 2x2 algs, also some pyraminx...
Oh well, I guess I know too many but still not enough! :lol:

p.s. I realy know some algs which I never use so that's pretty stupid :P

p.s2 I think that if you use a 2.5 look last layer (orient edges with last pair (6 algs) ) you can average 15/16 seconds...so 34 algs would be enough (6+7+21)
 
I use 28 (7 OLL/21 PLL), but I know upwards of 50. I never really took time to count all of the ones I know, but I only use the ones I like.
 
I probably know over 100 algs... Even if I don't include the F2L algs...

I know more algs for most OLL's/PLL's for example.

For the last layer I effectively use about 1 alg for every case, though. Well, for some cases, I use a different alg from certain angles.
 
I only know and use five algs for the Petrus Method and have an average time of around a minute 7 seconds (discarding highest and lowest times) according to the timer i got from this site. With more practice, Ill probably be able to cut that down to sub-minute averages. Most of my time comes from looking for the right cubes when forming the first two layers.
 
I got all my algs from Petrus's website lar5.com. They arent written in notation there, so I'll write them here, but you will have to go to the website to see how to orient the cube and when the algs should be used. Note also that these algorithms are only for the last layer and the first two layers should be built intuitively.


Niklas: L U' R' U L' U' R (for this, I orient the cube so that his left face is my front face)

Sune: R U R' U R U2 R'

Allan: L2 U' B F' L2 B' F U L2


these last two arent necessary to learn because all last layer edge permutations can be done with two allans, but I memorized them for convenience

Bert: L2 R2 D F2 L2 R2 B2 L2 R2 D' L2 R2

Arne: F2 L2 R2 B2 D B2 L2 R2 F2


sorry if I messed up on the notation, I double checked em for accuracy but Im not the best with it so there still might be a mistake.
 
Niklas looks like Anti-Sune to me
Sune is well known.
Using these 2 algs you can orient corners

Allan: I think this is an edge 3-cycle, but the first U' should be a U. Also it seems to be mirrored for the left-handed.

Bert is the Z-Cross, but I think much better algs exist for this, like Dan Knights or the 2-Gen

Arne is the Plus-Cross, but also much better algs exist for this, like r2R2U' r2R2U2 r2R2 U' r2R2, (also knows as M2U M2U2 M2U M2)

This doesn't seem to be enough to solve the entire cube. I am missing algs for edge-orientation (intuitively during F2L?) and for corner permuation (combinations of Niklas and Sune?)
 
his step 3 is to fix "bad edges" so that you dont have know any algs for edge permutation. after you finish the first two layers, the top cross will already be there.
 
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