grapefruit95
Member
If you don't know what CP parity is for Square-1:
It is essentially solving parity by learning 2 algs per CP case, one for if you have parity and one if you don't.
In total this is 16 algs. 8 of which you would have to learn anyway without CP parity. So really you are only learning 8 new algs.
Otherwise for full Vandenbergh you would need to learn 50 EP parity algs. This means you are simply cutting off 42 algs from being required, and the only disadvantage is a tiny bit more time recognizing the case.
HOW RECOGNITION WORKS
To make this easy to explain, first off, the U and D layers will have what look to be 3x3 PLLs on them, some are possible, and some would require you to disassemble a standard 3x3 and swap two pieces to solve, these are parity cases.
Lets begin by assigning each type of PLL a number:
If we have a W-Perm (a parity case) we have 1 If we then add a G Perm (not parity, so zero) to it, we end up with one. If our ending number is odd then we have parity and vice versa.
2 Y Perms (0+0) is an even number, no parity
2 O Perms (1+1) is an even number, no parity
1 U Perm and 1 F perm (1+1) no parity
1 Adj Swap and 1 T Perm (0+1) parity
1 Diag Swap and 1 V Perm (0+1) parity
Are you seeing it now? Good.
Hope that has convinced some of you to switch, I has really helped me improve. I would also like to mention that really you only need to learn 4 algs, because half of them a slight variants of others.
It is essentially solving parity by learning 2 algs per CP case, one for if you have parity and one if you don't.
In total this is 16 algs. 8 of which you would have to learn anyway without CP parity. So really you are only learning 8 new algs.
Otherwise for full Vandenbergh you would need to learn 50 EP parity algs. This means you are simply cutting off 42 algs from being required, and the only disadvantage is a tiny bit more time recognizing the case.
HOW RECOGNITION WORKS
To make this easy to explain, first off, the U and D layers will have what look to be 3x3 PLLs on them, some are possible, and some would require you to disassemble a standard 3x3 and swap two pieces to solve, these are parity cases.
Lets begin by assigning each type of PLL a number:
- All cases that would be solvable on a 3x3 = 0
- All cases that would require a disassembly to be solved = 1
If we have a W-Perm (a parity case) we have 1 If we then add a G Perm (not parity, so zero) to it, we end up with one. If our ending number is odd then we have parity and vice versa.
2 Y Perms (0+0) is an even number, no parity
2 O Perms (1+1) is an even number, no parity
1 U Perm and 1 F perm (1+1) no parity
1 Adj Swap and 1 T Perm (0+1) parity
1 Diag Swap and 1 V Perm (0+1) parity
Are you seeing it now? Good.
Hope that has convinced some of you to switch, I has really helped me improve. I would also like to mention that really you only need to learn 4 algs, because half of them a slight variants of others.
)
