Help with moving the last layer edges.

julesv

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I was using badmephistos algorithms on the part 3/3 of his beginner method, but a problem is always recurring... I get two solved sides, and only two edges need to be moved, but his algorithms, do a cycle of three edges, which doesnt help me, and puts me in some sort of never ending thingy. Help please?
 
(I think this is my second post in this forum lol)

You can't use a 3 cycle of edges to solve that, you'll have to permute those two edges only, which will also move the corners, but since you haven't solved them yet, you don't have to worry (I think, I'm not really sure which begginner method you're learning, the one I learned you solved: edge orientation, edge permutation, corner permutation and finnally corner orientation)

So to do this, what I used to do (because the algorithm is so easy and simple) was to adjust the upper face so that two edges matched with the underneath color, and I placed those faces in the front and the right faces so the "unsolved edges" where at the back and left faces (I'm not 100% sure, I don't have a cube in my hands right now, if this is wrong, try the following algorithm in a solved cube and see what it does) and do (this algorithm is called Sune, you may have heard it before):

R U R' U R U2 R'

And if you adjust by doing U' I think, you'll have the four edges in their correct position.

Sorry if this is not what you have to solve in this step in the begginer method you're learning, but I hope it helps :)
 
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So the four corners are solved (in their correct position) but two edges are not permuted?

This is no possible as an even number of pieces can't be swapped in a cube (this is some kind of "rule" the cube has, just like there can't be just one edge unoriented, for instance)

So the only thing I can tell you if this is the case, is to unassemble the cube and assemble it in a solved state so you know the cube is "solvable" (does this word exist? lol).
Maybe what happened is that you took some pieces appart and when you assembled it you did it in an... illegal state, with a permutation parity (an even number of pieces swapped, which is impossible to solve)

Or maybe I'm just not understanding :p
 
Haha don't worry, it happens.

So now what happens is that you would have solved the cube :D (and you'll solve it again when you assemble it again in a correct position) Congratulations ;)
 
From what I understood,
View from the top of the cube:

X X X
X X Y
X Y X

And the two Y's need to be switched?

That's not possible... Check your cube and make sure if all your corners are in their right postions... If they are, the only thing you can do is to pull out those edge pieces and interchange their positions...
 
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