guusrs
Veteran
FMC solution:
scramble: R U2 B2 F U F' L2 F' R2 D2 F L D' R' D U' R U
I took the inverse scramble so: U' R' U D' R D L' F' D2 R2 F L2 F U' F' B2 U2 R'
Premove: B2
start: L D L, oooh everything looks nice now... lets make the block on the back before the block that I focussed on in the first place:
R' F B2 D, so nice everythingF2. Now it's possible to finish the F2L minus one pair with U' L and do this in only 10 moves and a premove.
instead I solved all edges:
L L U F U' F' L'. Then the first commutator: L F L' B L F' L' B'. Where some stuff cancels out nicely.
Last 3 corners: B (setup, L F' L' B' L F L' ) B' L' B'. Where the last move skips a move with the premove:
Total:
L D L R' F B2 D F2 L2 U F U' L' B L F' L F' L' B' L F L' B L' B (26)
I'm sure there is something nicer to find and at least the last commutator could've been implemented somewhere in the solution so it would skip some more moves. I didn't try this because I know I always need a lot time to finally get an inverted solution to work on the original scramble...
Yay NRSorry Guus...
Erik,
It is a splendid solution, You deserve that NR! And you beated Arnaud (who was a NR-holder too)!
I'm not sure If I would have found that 10 moves start. I will found the inverse scramble with pre-move B2
(because on the normal scramble the first move B2 makes extra pairs). But if I would have found L D L as a start.....
....I will use your frame: L.D L R' F B2 D F2 L2 U F U' L' B L F' L' B (18), sticker the 3 corners, solve, rescramble and after 2 minutes find: L U2 L' D L U2 L' D' for inserting at the dot. 5 moves cancel, resulting in 21 moves.
So solve for regular scramble: B' L F L' B' L U F' U' L2 F2 D' B2 F' R U2 L' D' L U2 L2 (21)
I should not skip dutch competitions......
Gus