RyanReese09
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- May 16, 2010
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FULL OLL+PLL
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78
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78
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apparently this method has an OLL skip all the time. apparently. I shall force myself to read more chinese later. >_>
It's very very fast. CFOP is 4 steps. CZZ 3 steps only.
It's very very fast. CFOP is 4 steps. CZZ 3 steps only.
Let me guess:
C-cross
Z-ZOMGWTFBBQPIZZAf2l
Z-ZOMG!!HUSHIDIUW1LLL ?
Seriously, can you please elaborate?
It sounds to me like some method nobody's ever heard of just appeared out of nowhere and kicked cfop in the face.
It's very very fast. CFOP is 4 steps. CZZ 3 steps only.
Its 11 if you see pairing up and insert as different stepsIt's very very fast. CFOP is 4 steps. CZZ 3 steps only.
First of all, chances are CZZ is, like most other people are saying, bs.
But, I thought I should point out that while CFOP has four totally different steps, F2L is essentially four steps on its own, making CFOP a seven step method.
Its 11 if you see pairing up and insert as different steps![]()
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
Its 11 if you see pairing up and insert as different steps![]()
That's just dumb. lol.
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
Its 11 if you see pairing up and insert as different steps![]()
That's just dumb. lol.
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
hmmm I wonder how many steps roux and zz have
I don't understand why each piece is a step and UR+UL aren't 1 D: I'd call it a 6/7 step depending on if you know full CMLL or not.Its 11 if you see pairing up and insert as different steps![]()
That's just dumb. lol.
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
hmmm I wonder how many steps roux and zz have
5 Pieces per block = 10...
CMLL
Orient edges = 1 if you don't suck
UR + UL = Pairing then placing = 2
M slice = 1
15 steps in Roux![]()