does anybody know the weird method of CZZ?

this was what i wanted to tell to Joey a few days ago when my IRC chat room crashed and never got recovered after that:(

on topic, that random guy said that he didnt like the way making it public, which i thought it was just BS
 
It's very very fast. CFOP is 4 steps. CZZ 3 steps only.

Let me guess:
C-cross
Z-ZOMGWTFBBQPIZZAf2l
Z-ZOMG!!HUSHIDIUW1LLL ?:(

Seriously, can you please elaborate?
It sounds to me like some method nobody's ever heard of just appeared out of nowhere and kicked cfop in the face.
 
It's very very fast. CFOP is 4 steps. CZZ 3 steps only.

First of all, chances are CZZ is, like most other people are saying, bs.

But, I thought I should point out that while CFOP has four totally different steps, F2L is essentially four steps on its own, making CFOP a seven step method.
 
It's very very fast. CFOP is 4 steps. CZZ 3 steps only.

First of all, chances are CZZ is, like most other people are saying, bs.

But, I thought I should point out that while CFOP has four totally different steps, F2L is essentially four steps on its own, making CFOP a seven step method.
Its 11 if you see pairing up and insert as different steps:p

But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
 
Its 11 if you see pairing up and insert as different steps:p

That's just dumb. lol.

But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.
 
Its 11 if you see pairing up and insert as different steps:p

That's just dumb. lol.

But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.

hmmm I wonder how many steps roux and zz have
 
Its 11 if you see pairing up and insert as different steps:p

That's just dumb. lol.

But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.

hmmm I wonder how many steps roux and zz have

5 Pieces per block = 10...
CMLL
Orient edges = 1 if you don't suck
UR + UL = Pairing then placing = 2
M slice = 1

15 steps in Roux :)
 
Its 11 if you see pairing up and insert as different steps:p

That's just dumb. lol.

But essentially f2ls are similar and can be counted as one 'step' while cross, oll and pll are substantially different
So what if they're similar? Just because they're similar doesn't mean you solve all four F2L pairs at the same time. When it comes to counting the number of individual steps in a CFOP solve, each F2L pair is really one step (especially for slower people who have significant pauses between each pair). As a whole though, CFOP has four unique steps, yes.

hmmm I wonder how many steps roux and zz have

5 Pieces per block = 10...
CMLL
Orient edges = 1 if you don't suck
UR + UL = Pairing then placing = 2
M slice = 1

15 steps in Roux :)
I don't understand why each piece is a step and UR+UL aren't 1 D: I'd call it a 6/7 step depending on if you know full CMLL or not.

Is F2L a 4(cross)+8(F2L)+2(OLL+PLL) step method then?

edit: When I think about it, you were probably wearing your trollface when writing that.
 
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