fun at the joy
Veteran
haven't really started but I'll do it maybe today or tomorrow
-
Welcome to SpeedSolving.com — the world’s largest puzzle community!
You’re currently browsing as a guest, which means you have limited access to discussions, resources, member profiles, and community features.
Join 50,000+ cubers and puzzle enthusiasts from around the world to ask questions, share solves, improve faster, and be part of the community.
Registration is free, fast, and easy — create your account today.
Already a member? Log in here to hide this message and start participating.
Cube Exploring Competition : Kompetition 2
- Thread starter kubesolver
- Start date
brododragon
Veteran
Bump. Updated.
kubesolver
Premium Member
- Joined
- Nov 15, 2019
- Messages
- 446
This competition got 4 contestants. Thank you for participation. This time the winner is not clear as there are some answers that I should probably consider wrong.
The first place goes either to @TipsterTrickster or @WoowyBaby.
The problems are the following:
@TipsterTrickster gave answer to 2A which had F2L -1 solved, so it already had 2x2x2 blocks solved so he should get 0 points for problem 2A. His solution was a 7-moved to a 2x2x2 on FR slot. So I think it wouldn't break the spirit of a competition if he could resubmit, but on the other hand I feel the rules were rather clear. Would love to hear what other contestants think about it.
In this case the winner should be @WoowyBaby, but he gave an amazing short 2.x answer to both generation problems (4.3 and 4.3A), but I'm not convinced if they are correct and he didn't reply to me in PM with any explaination how to use these sequences to actually solve any state. (Edit: he did now and his answer is actually correct!)
I think it might be correct given, that I could come up with a complex 2.x solution to this problem.
Other interesting problem was recursion number. The recursion number of a sequence is a lowest common multiply(LCM) of the length of all cycles.
We can have 9 * 5 cycles of corners giving 45 as a perfect answer for a 2x2x2 cube and for edges we can additionally make a cycle of length 11 with an edge twist making the max recursion number 9 * 5 * 11 * 2 = 990.
Surprisingly some people have answered with Inifinity to a 1.INF problem getting painful 0 points. All nxnxn cubes have at most 24 pieces of one kind, so the recusion number can't be higher than LCM of (1,2,3,4,...24) which is 2^4 × 3^2 × 5 × 7 × 11 × 13 × 17 × 19 × 23 = 5354228880 and it can be squezzed on a 6x6x6. @TipsterTrickster was the closest with finding the optimal solution, but packed on a 7x7x7.
Other problems turned out to be rather easy.
So current standings are like this, but this is pending explanaition from @WoowyBaby about his solutions to the 4.X problems. If @TipsterTrickster will make a claim that the problem description was misleading and will like have his solution for 2A scored 7 and nobody objects I will probably accept it.
So the final standings might change.
Here are the final standings:
Edit: clarification from @WoowyBaby received.
Edit: As everyone agreed I gave TipsterTrickster 100 for 2A and WoowyBaby didn't provide a proof for his 4.3A answer so I gave him 50.5 there (I think it's fair to assume he would find that.
The first place goes either to @TipsterTrickster or @WoowyBaby.
The problems are the following:
@TipsterTrickster gave answer to 2A which had F2L -1 solved, so it already had 2x2x2 blocks solved so he should get 0 points for problem 2A. His solution was a 7-moved to a 2x2x2 on FR slot. So I think it wouldn't break the spirit of a competition if he could resubmit, but on the other hand I feel the rules were rather clear. Would love to hear what other contestants think about it.
In this case the winner should be @WoowyBaby, but he gave an amazing short 2.x answer to both generation problems (4.3 and 4.3A), but I'm not convinced if they are correct and he didn't reply to me in PM with any explaination how to use these sequences to actually solve any state. (Edit: he did now and his answer is actually correct!)
4.3: 2.03
(R z, y)
4.3A: 2.05
(R L', U F D)
(R z, y)
4.3A: 2.05
(R L', U F D)
I think it might be correct given, that I could come up with a complex 2.x solution to this problem.
The idea: OP-BLD style. We have one corner buffer and one edge buffer.
The idea is exactly the same for corners and edges.
1) We select one buffer piece and one target piece.
2) We come up with a sequence that cycles over all pieces except of a buffer
3) We use a swap algorithm that swaps buffer with target and we don't worry about orientation.
4) Swap algorithm also flips two edges that are neither target nor buffer so we can orientate pieces when they are all in their correct locations.
Alg1 SETUP = CORNER_SETUP EDGE_SETUP
Alg2 FLIP_AND_SWAP = JPERM + flip 2 corners + flip 2 edges = F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2
Where the exact algs are:
CORNER_SETUP = (F L D L D' F' R2 D L' D' L F L2 F' R2) //CORNER_SETUP
EDGE_SETUP = (U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2) //EDGE_SETUP
CORNER_SETUP is a 7-cycle, while EDGE_SETUP is 11-cycle so
EDGE_SETUP = (SETUP)56
CORNER_SETUP = (SETUP)22
flip(S,F) = (S2 F S2) (F S F' S' F' S F S' F S F S') (S2 F S2)'
We have two flipping algs (one for corners and one for edges):
flip(CORNER_SETUP, FLIP_AND_SWAP) = change orientation of a buffer and target corner
flip(EDGE_SETUP, FLIP_AND_SWAP) = change orientation of a buffer and target edge
To solve a cube you do 4 steps.
1) Permutate corners
2) Permutate edges
3) Orient corners and edges
1) Look what piece is in a buffer corner slot. Let's say that it's a piece X.
Call the CORNER_SETUP enough times so that the piece currently in X's spot is in target. Execute SWAP, Undo the setup.
Repeat until all Corners are in place.
2) Same but for edges.
Similar like in OP-BLD method every time we swap two edges we also swap two corners, but when all edges are in place all corners will be as well because parity.
3) Flip corners and edges.
Find a piece that has wrong orientation, bring it to the target location and execute flipping alg.
Cube Solved
The idea is exactly the same for corners and edges.
1) We select one buffer piece and one target piece.
2) We come up with a sequence that cycles over all pieces except of a buffer
3) We use a swap algorithm that swaps buffer with target and we don't worry about orientation.
4) Swap algorithm also flips two edges that are neither target nor buffer so we can orientate pieces when they are all in their correct locations.
Alg1 SETUP = CORNER_SETUP EDGE_SETUP
Alg2 FLIP_AND_SWAP = JPERM + flip 2 corners + flip 2 edges = F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2
Where the exact algs are:
CORNER_SETUP = (F L D L D' F' R2 D L' D' L F L2 F' R2) //CORNER_SETUP
EDGE_SETUP = (U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2) //EDGE_SETUP
CORNER_SETUP is a 7-cycle, while EDGE_SETUP is 11-cycle so
EDGE_SETUP = (SETUP)56
CORNER_SETUP = (SETUP)22
flip(S,F) = (S2 F S2) (F S F' S' F' S F S' F S F S') (S2 F S2)'
We have two flipping algs (one for corners and one for edges):
flip(CORNER_SETUP, FLIP_AND_SWAP) = change orientation of a buffer and target corner
flip(EDGE_SETUP, FLIP_AND_SWAP) = change orientation of a buffer and target edge
To solve a cube you do 4 steps.
1) Permutate corners
2) Permutate edges
3) Orient corners and edges
1) Look what piece is in a buffer corner slot. Let's say that it's a piece X.
Call the CORNER_SETUP enough times so that the piece currently in X's spot is in target. Execute SWAP, Undo the setup.
Repeat until all Corners are in place.
2) Same but for edges.
Similar like in OP-BLD method every time we swap two edges we also swap two corners, but when all edges are in place all corners will be as well because parity.
3) Flip corners and edges.
Find a piece that has wrong orientation, bring it to the target location and execute flipping alg.
Cube Solved
F U2 L2 B2 F' U L2 U R2 D2 L' B L2 B' R2 U2
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)2: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)6: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)7: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)3: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)9: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)1: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
(F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2)
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)5: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)10: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
(F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2)
[(F L D L D' F' R2 D L' D' L F L2 F' R2)2: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)3: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)4: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)6: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)5: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
//at this point all pieces are in place and we can do the flipping
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)2: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)6: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)7: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)3: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)9: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)1: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
(F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2)
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)5: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(U F2 U L2 B R2 U2 R2 B L2 D R2 U R2 L2 U2)10: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
(F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2)
[(F L D L D' F' R2 D L' D' L F L2 F' R2)2: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)3: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)4: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)6: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
[(F L D L D' F' R2 D L' D' L F L2 F' R2)5: F' U' B2 U' L U' L' F U2 L2 U2 L2 B2 D' B2 D' R2 D2 R2 B2 R2]
//at this point all pieces are in place and we can do the flipping
Other interesting problem was recursion number. The recursion number of a sequence is a lowest common multiply(LCM) of the length of all cycles.
We can have 9 * 5 cycles of corners giving 45 as a perfect answer for a 2x2x2 cube and for edges we can additionally make a cycle of length 11 with an edge twist making the max recursion number 9 * 5 * 11 * 2 = 990.
Surprisingly some people have answered with Inifinity to a 1.INF problem getting painful 0 points. All nxnxn cubes have at most 24 pieces of one kind, so the recusion number can't be higher than LCM of (1,2,3,4,...24) which is 2^4 × 3^2 × 5 × 7 × 11 × 13 × 17 × 19 × 23 = 5354228880 and it can be squezzed on a 6x6x6. @TipsterTrickster was the closest with finding the optimal solution, but packed on a 7x7x7.
Other problems turned out to be rather easy.
So the final standings might change.
Here are the final standings:
1. TipsterTrickster 867.00
2. WoowyBaby 790.32
3. brododragon 714.34
4. CuberStacke 692.01
Problem 1.3:
brododragon: answer: 315.0 score: 83.39835766034379
CuberStacke: answer: 210.0 score: 77.52009653651764
TipsterTrickster: answer: 990.0 score: 100.0
WoowyBaby: answer: 720.0 score: 95.38319290627571
Problem 1.2:
brododragon: answer: 36.0 score: 94.13807890996732
CuberStacke: answer: 30.0 score: 89.348540639004
TipsterTrickster: answer: 45.0 score: 100.0
WoowyBaby: answer: 45.0 score: 100.0
Problem 1.INF:
brododragon: answer: 2280.0 score: 37.799262300459965
CuberStacke: answer: 210.0 score: 26.140523935193762
TipsterTrickster: answer: 764889840.0 score: 100.0
WoowyBaby: answer: 720.0 score: 32.164132251914126
Problem 2A:
brododragon: answer: 7.0 score: 100.0
CuberStacke: answer: 7.0 score: 100.0
TipsterTrickster: answer: 7.0 score: 100.0
WoowyBaby: answer: 7.0 score: 100.0
Problem 2B:
brododragon: answer: 6.0 score: 100.0
CuberStacke: answer: 6.0 score: 100.0
TipsterTrickster: answer: 6.0 score: 100.0
WoowyBaby: answer: 6.0 score: 100.0
Problem 4.3:
brododragon: answer: 3.03 score: 67.00
CuberStacke: answer: 3.03 score: 67.00
TipsterTrickster: answer: 3.03 score: 67.00
WoowyBaby: answer: 2.03 score: 100.00
Problem 4.3A:
brododragon: answer: 5.05 score: 62.77
CuberStacke: answer: 5.05 score: 62.77
TipsterTrickster: answer: 3.17 score: 100.00
WoowyBaby: answer: 5.05 score: 62.77
Problem 5.B:
brododragon: answer: 13.0 score: 100.00
CuberStacke: answer: 13.0 score: 100.00
TipsterTrickster: answer: 13.0 score: 100.00
WoowyBaby: answer: 13.0 score: 100.00
Problem 5.B2:
brododragon: answer: 13.0 score: 69.23
CuberStacke: answer: 13.0 score: 69.23
TipsterTrickster: answer: 9.0 score: 100.00
WoowyBaby: answer: 9.0 score: 100.00
2. WoowyBaby 790.32
3. brododragon 714.34
4. CuberStacke 692.01
Problem 1.3:
brododragon: answer: 315.0 score: 83.39835766034379
CuberStacke: answer: 210.0 score: 77.52009653651764
TipsterTrickster: answer: 990.0 score: 100.0
WoowyBaby: answer: 720.0 score: 95.38319290627571
Problem 1.2:
brododragon: answer: 36.0 score: 94.13807890996732
CuberStacke: answer: 30.0 score: 89.348540639004
TipsterTrickster: answer: 45.0 score: 100.0
WoowyBaby: answer: 45.0 score: 100.0
Problem 1.INF:
brododragon: answer: 2280.0 score: 37.799262300459965
CuberStacke: answer: 210.0 score: 26.140523935193762
TipsterTrickster: answer: 764889840.0 score: 100.0
WoowyBaby: answer: 720.0 score: 32.164132251914126
Problem 2A:
brododragon: answer: 7.0 score: 100.0
CuberStacke: answer: 7.0 score: 100.0
TipsterTrickster: answer: 7.0 score: 100.0
WoowyBaby: answer: 7.0 score: 100.0
Problem 2B:
brododragon: answer: 6.0 score: 100.0
CuberStacke: answer: 6.0 score: 100.0
TipsterTrickster: answer: 6.0 score: 100.0
WoowyBaby: answer: 6.0 score: 100.0
Problem 4.3:
brododragon: answer: 3.03 score: 67.00
CuberStacke: answer: 3.03 score: 67.00
TipsterTrickster: answer: 3.03 score: 67.00
WoowyBaby: answer: 2.03 score: 100.00
Problem 4.3A:
brododragon: answer: 5.05 score: 62.77
CuberStacke: answer: 5.05 score: 62.77
TipsterTrickster: answer: 3.17 score: 100.00
WoowyBaby: answer: 5.05 score: 62.77
Problem 5.B:
brododragon: answer: 13.0 score: 100.00
CuberStacke: answer: 13.0 score: 100.00
TipsterTrickster: answer: 13.0 score: 100.00
WoowyBaby: answer: 13.0 score: 100.00
Problem 5.B2:
brododragon: answer: 13.0 score: 69.23
CuberStacke: answer: 13.0 score: 69.23
TipsterTrickster: answer: 9.0 score: 100.00
WoowyBaby: answer: 9.0 score: 100.00
Edit: clarification from @WoowyBaby received.
Edit: As everyone agreed I gave TipsterTrickster 100 for 2A and WoowyBaby didn't provide a proof for his 4.3A answer so I gave him 50.5 there (I think it's fair to assume he would find that.
Last edited:
Cuberstache
Veteran
- Joined
- May 7, 2018
- Messages
- 1,059
- Location
- Washington State, USA
- WCA
- 2016DAVI02
- YouTube
- Visit Channel
I guess it really doesn't say anything about other 2x2x2s being solved. I interpreted it to be that all yellow 2x2x2s had to be x moves to get a score of x but the rules actually aren't as clear as I thought they were...
EDIT: What was the 9-move solution to solve the B2?
WoowyBaby
Veteran
R' L U2 F2 D2 R L' F2 U2 (9)
There are other solutions as well. (I believe 4 distinct)
Edit: Cube Explorer spits out this-
Searching depth 9
U D' R2 F2 L2 U' D F2 R2 (9f*)
U2 R2 L2 D2 F2 U2 R2 L2 D2 (9f*)
U2 R2 L2 D2 F2 D2 R2 L2 U2 (9f*)
U2 F2 R' L D2 F2 U2 R L' (9f*)
U' D L2 F2 R2 U D' F2 L2 (9f*)
R L' D2 F2 U2 R' L F2 D2 (9f*)
R2 U2 D2 L2 F2 R2 U2 D2 L2 (9f*)
R2 U2 D2 L2 F2 L2 U2 D2 R2 (9f*)
R2 F2 U D' L2 F2 R2 U' D (9f*)
R' L U2 F2 D2 R L' F2 U2 (9f*)
D2 R2 L2 U2 F2 U2 R2 L2 D2 (9f*)
D2 R2 L2 U2 F2 D2 R2 L2 U2 (9f*)
D2 F2 R L' U2 F2 D2 R' L (9f*)
L2 U2 D2 R2 F2 R2 U2 D2 L2 (9f*)
L2 U2 D2 R2 F2 L2 U2 D2 R2 (9f*)
L2 F2 U' D R2 F2 L2 U D' (9f*)
Searching depth 10
U D' R2 F2 L2 U' D F2 R2 (9f*)
U2 R2 L2 D2 F2 U2 R2 L2 D2 (9f*)
U2 R2 L2 D2 F2 D2 R2 L2 U2 (9f*)
U2 F2 R' L D2 F2 U2 R L' (9f*)
U' D L2 F2 R2 U D' F2 L2 (9f*)
R L' D2 F2 U2 R' L F2 D2 (9f*)
R2 U2 D2 L2 F2 R2 U2 D2 L2 (9f*)
R2 U2 D2 L2 F2 L2 U2 D2 R2 (9f*)
R2 F2 U D' L2 F2 R2 U' D (9f*)
R' L U2 F2 D2 R L' F2 U2 (9f*)
D2 R2 L2 U2 F2 U2 R2 L2 D2 (9f*)
D2 R2 L2 U2 F2 D2 R2 L2 U2 (9f*)
D2 F2 R L' U2 F2 D2 R' L (9f*)
L2 U2 D2 R2 F2 R2 U2 D2 L2 (9f*)
L2 U2 D2 R2 F2 L2 U2 D2 R2 (9f*)
L2 F2 U' D R2 F2 L2 U D' (9f*)
Searching depth 10
Cuberstache
Veteran
- Joined
- May 7, 2018
- Messages
- 1,059
- Location
- Washington State, USA
- WCA
- 2016DAVI02
- YouTube
- Visit Channel
I was literally about to reply with this hahaha. I'm surprised there are so many. That's really cool.
WoowyBaby
Veteran
Although, If you count inverses, rotations, and mirrors as the same, there are effectively only 2 different 9-move solutions to it.
TipsterTrickster
Veteran
I resubmitted my solution as <my solution> y *4. I guess I misinterpreted the rules as "hardest possible hardest possible 2x2x2" so for example if there was a 3 move 2x2 but also a 7 move 2x2 the 7 move 2x2 would be the answer. I'm ok with whatever you guys decide and think is fair.
brododragon
Veteran
That makes sense. I originally was against you resubmitting, but I'm fine with it after hearing your reasoning.
Cuberstache
Veteran
- Joined
- May 7, 2018
- Messages
- 1,059
- Location
- Washington State, USA
- WCA
- 2016DAVI02
- YouTube
- Visit Channel
Yeah, it's pretty easy to do what he said and just set up the same case for all four 2x2x2s so I think it's fine to give him 7 points.
kubesolver
Premium Member
- Joined
- Nov 15, 2019
- Messages
- 446
Ok. So after some discussions and considering what is fair I have made the following calls:
@TipsterTrickster gets 100 points for 2A
Those who anwered INF to 1.INF get points for the number they provided in 1.3 instead of 0 points.
@WoowyBaby gave the answer he can't prove for the 4.3A so I changed his answer to 5.05 everyone else gave as I think 0 points would be too harsh there.
After these updates here are the final standings.
100$ goes to @TipsterTrickster.
1. TipsterTrickster 867.00
2. WoowyBaby 790.32
3. brododragon 714.34
4. CuberStacke 692.01
In the meantime I'm working on the problems for another Kompetition which will be about other puzzles than 3x3. but I will try to think a little more about problems to maybe get a higher participation
@TipsterTrickster gets 100 points for 2A
Those who anwered INF to 1.INF get points for the number they provided in 1.3 instead of 0 points.
@WoowyBaby gave the answer he can't prove for the 4.3A so I changed his answer to 5.05 everyone else gave as I think 0 points would be too harsh there.
After these updates here are the final standings.
100$ goes to @TipsterTrickster.
1. TipsterTrickster 867.00
2. WoowyBaby 790.32
3. brododragon 714.34
4. CuberStacke 692.01
In the meantime I'm working on the problems for another Kompetition which will be about other puzzles than 3x3. but I will try to think a little more about problems to maybe get a higher participation
brododragon
Veteran
Almost all of my cube theory knowledge came directly by participating in the Kompetition, so I'd count it as a success.
WoowyBaby
Veteran
Congratulations to @TipsterTrickster !! After a close second on the first Kompetition, it seems right to win this one!
But wait. Let's pause for a second. Did @TipsterTrickster provide proof for his 4.3 solutions? o_O
I'll assume he has provided proof for those. In that case, well done and I hope you enjoy your $100 gift card prize
But wait. Let's pause for a second. Did @TipsterTrickster provide proof for his 4.3 solutions? o_O
I'll assume he has provided proof for those. In that case, well done and I hope you enjoy your $100 gift card prize
kubesolver
Premium Member
- Joined
- Nov 15, 2019
- Messages
- 446
His solution is a very elegant one kind of similar to the solutions to 5.B
It's two center swap algorithms and U.
So e.g. R = move white center to the right face and do a U.
It's two center swap algorithms and U.
So e.g. R = move white center to the right face and do a U.
TipsterTrickster
Veteran
Awesome! Here are my solutions for anyone interested.
This was a lot of fun and I am super exited for the next one! Thank you for doing these.
1.3: 990
D' L2 B' L' U2 B' D2 F R F R2 B U' B' D2
1.2: 45
U R' F R2 F' R D B2 D2
1.INF: 764889840
On a 7x7 5354228880/7 = 764889840
Number = number of pieces cycled
F = 2 pieces flipped, both being in separate cycles
T = 2 pieces twisted, both being in separate cycles, one twisted clockwise and the other counter clockwise.
2A: F R’ F’ R2 U’ R’ U2 F’ U’ F (7 move 222) later revised to: F R’ F’ R2 U’ R’ U2 F’ U’ F y F R’ F’ R2 U’ R’ U2 F’ U’ F y F R’ F’ R2 U’ R’ U2 F’ U’ F y F R’ F’ R2 U’ R’ U2 F’ U’ F y
2B: F R2 F U’ R’ U2 F R’ (6 move cross)
4.3: 3.03
(U, x, y)
4.3A: 3.17
(U, R L’ U D’ F’ B R L’, R L’ F’ B U’ D R L’)
5.B: 13
R’ L U2 D2 R’ L F’ R L’ U2 D2 R L’
5.B2: 9
U2 R2 L2 D2 F2 D2 R2 L2 U2
D' L2 B' L' U2 B' D2 F R F R2 B U' B' D2
1.2: 45
U R' F R2 F' R D B2 D2
1.INF: 764889840
On a 7x7 5354228880/7 = 764889840
Number = number of pieces cycled
F = 2 pieces flipped, both being in separate cycles
T = 2 pieces twisted, both being in separate cycles, one twisted clockwise and the other counter clockwise.
2A: F R’ F’ R2 U’ R’ U2 F’ U’ F (7 move 222) later revised to: F R’ F’ R2 U’ R’ U2 F’ U’ F y F R’ F’ R2 U’ R’ U2 F’ U’ F y F R’ F’ R2 U’ R’ U2 F’ U’ F y F R’ F’ R2 U’ R’ U2 F’ U’ F y
2B: F R2 F U’ R’ U2 F R’ (6 move cross)
4.3: 3.03
(U, x, y)
4.3A: 3.17
(U, R L’ U D’ F’ B R L’, R L’ F’ B U’ D R L’)
5.B: 13
R’ L U2 D2 R’ L F’ R L’ U2 D2 R L’
5.B2: 9
U2 R2 L2 D2 F2 D2 R2 L2 U2
Similar threads
[Member Intro]
Exploring the World of Speedcubing, One Cube at a Time :O
