Chances of 1 look LL if you know ELL (and CLL?)

[Erik]

What are the chances that you can solve the LL in one algorithm if you'd know OLL, PLL, ELL and CLL? (assumed you know when the CLL will skip)

 

[Sébastien.felix]

I think thats about 3.2% of chances to have a 1 alg LL when you know these sets of algs:
edges oriented+corners oriented+all pieces solved=(1/8)*(1/27)*(1/72)=>LL skip
edges oriented+corners oriented=(1/8)*(1/27)=>OLL skip
edges oriented+corners non-oriented=(1/8)*(26/27)*(1/12)=>apply CLL, 1 step LL when edge permutation is skipped (1/12).
edges non-oriented+corners oriented=(7/8)*(1/27)*(1/6)=>apply ELL, 1 step LL when corner permutation is skipped (1/6).
edges non-oriented+corners non oriented=(7/8)*(26/27)*(1/72)=>apply OLL, 1 step when PLL is skipped (1/72)
the sum of all these odds is about 0.0318

1 cube out 32

 

[Lt-UnReaL]

I'm guessing ELL and CLL would be EOLL and COLL? Where do I learn ELL?

 

[Erik]

no I'm NOT referring to EOLL and COLL.....................................................................................................................

 

[Kenneth]

Chances of skips are:

CLL 1:192
ELL 1:96
OLL 1:216 --> do PLL

PLL solves both CLL and ELL in one alg, not pure CLL/ELL but it's the way most people solve LL if orientation skips. Pure would be CPLL + EPLL.

You newer do OLL if all pieces are unoriented when you are attemting to do CLL/ELL, why would you?

Edit: if you are advanced you can also learn the ELL cases where corner orientation skips but not permutation, there are 29 cases for each configuration = 3*29 = 87 totaly. that makes one alg LL's in 1:27