Call Me Cray - Counting my 3x3 solves for 1 year!

Well I've forgotten again. Good luck to you remembering them all. However, as I always keep a daily tally of Skips, I'll include them here and hopefully until the end of the year.

So far this year (end of Jan 2nd 2014):


PLL Skips: 6
OLL: Skips:2
LL Skips: 0

PB Lucky: 8.34 (PLL)
PB Non-lucky: 10.83
Sub-10's: 4
Sub-9''s: 1
 
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Going to have to become pretty attached to these guys :)

counters.jpg
 
But seriously though, can someone fix the title because it's bugging the poop out of me and clearly I'm going to have to put up with seeing it on a regular basis throughout this year.
 
This is so cool! I really hope you succeed. I'm most curious to see how close your solves are to the mathematical probability of a OLL/PLL/LL skip. As of solve 583 you're averaging a PLL skip ~ 1/83 solves while you're averaging an OLL skip ~ 1/193 solves!

PLL skip: 1/72
OLL skip: 1/216
LL skip: 1/15552

For those who didn't know. :)
 
I will also be counting all of my 3x3 solves for the year. I am keeping most of the times in excel and will be estimating the number of un-timed solves. Here is my progress so far:


569 timed solves
110 un-timed solves
----------------------

679 total solves

I haven't been keeping track of PLL skips, but I know I've had at least 5. I also have had 1 LL skip!!
 
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Funny thing I found this thread, because to get back again into cubing, I wanted to track all my timed solves of the year and started an excel sheet for that.

However, I only count timed solves, no skips.

Here are my statistics:
- Number of solves: 180 (I know, I have not that much time)
- PBs(Single / ao5 / ao12): 17.29 / 23.59 / 25.57
- Mean of all solves: 29.60
- Worst time: 49.02
 
It's not nothing but a guess. It is most of my solves + an estimate of the ones I think I forgot to count.

So almost the correct number?
So an approximate estimation?
So a guess.

I couldn't put that much effort in and not have THE number at the end.
It would invalidate all the effort for me.
 
So almost the correct number?
So an approximate estimation?
So a guess.

I'm an engineer, so a number within 25% error is good enough for me. Luckily, as of right now I'm only at 2%. :)

I couldn't put that much effort in and not have THE number at the end.
It would invalidate all the effort for me.

I guess you must be perfect then. Most people aren't.
 
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