Blindsolving Accomplishment Thread

my first blind solve was a success!
but i didnt start the timer during memo cause that would take forever.
i used old pochmann and i got 9:56 speed bld.
i memo with visualizing images from the colour pairs. corner orientation is annoying to remember.
 
my first blind solve was a success!
but i didnt start the timer during memo cause that would take forever.
i used old pochmann and i got 9:56 speed bld.
i memo with visualizing images from the colour pairs. corner orientation is annoying to remember.
You should really move on to using a lettering scheme (look for the speffz in the wiki). You'll be surprised how quickly you can get used to it.
 
Finally sub-2! 3BLD: 1:59.51
I have a scramble, but I think I scrambled wrong. It was pretty easy, 6 corner targets and a twisted corner and 8 edge targets with 2 flipped edges. It would have been much easier had I not had a ton of cycle breaks. My previous PB was 2:2x, but I hardly practice.

Edit: The solve after: 1:50.97 B' L2 D2 U2 B R2 B L2 F2 R2 D2 L' R2 D R' B2 F D2 R2 D' F2 Scramble in Red front Blue top (my orientation)
Method: M2 OP

I guess this is what happens when I practice...
 
Last edited:
3BLD: 30.30
D2 U2 L2 U D' R' L' B' F2 R L B2 F2 U2 D2 R U2 B' F2 L' R D' B' F2 D2
rekonstruction

Corners
  • y' R' D2 R D R' D R L D2 L' D' L D' L'
  • [R' D R, U2] y
  • [R D R', U']
  • [x'; R' D' R, U']
Edges:
  • x U' M U' M U2 M' U' M' U x'
  • L U' M U' M' U2 M U' M' U L'
  • L2 M U M' U2 M U M'
  • [y'; U M2 U', R'] y'(I didnt cancel setup y' turn)
  • R' U2 R U2 R' F R U R' U' R' F' R2 U'

PB. Memo propably sub10, I was paradoxicaly very dissapointed :P
 
3BLD: 30.30
D2 U2 L2 U D' R' L' B' F2 R L B2 F2 U2 D2 R U2 B' F2 L' R D' B' F2 D2
rekonstruction

Corners
  • y' R' D2 R D R' D R L D2 L' D' L D' L'
  • [R' D R, U2] y
  • [R D R', U']
  • [x'; R' D' R, U']
Edges:
  • x U' M U' M U2 M' U' M' U x'
  • L U' M U' M' U2 M U' M' U L'
  • L2 M U M' U2 M U M'
  • [y'; U M2 U', R'] y'(I didnt cancel setup y' turn)
  • R' U2 R U2 R' F R U R' U' R' F' R2 U'

PB. Memo propably sub10, I was paradoxicaly very dissapointed :P

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What do the brackets mean? Could someone explain it to me, please?
 
I still don't get it :D
It's a short way to write a commutator, commutators are algorithms of the form:
A B A' B'
where A is a sequence of moves, B is a sequence of moves, A' is the inverse of A (for example if A is U R than A' is R' U'), B' is the inverse of B
To write A B A' B you could also write [A, B].

Commutators are useful for affecting only a small portion of the cube and are good for advanced blind solving, because they allow you to cycle 3 pieces without affecting any other piece on the cube, allowing you to solve the cube in groups of 3 pieces at a time.
 
Is just another notation

[A, B] stands for A B A' B' (being A & B any sequence of moves)
[A; B] stands for A B A'

It is not just a shorter notation method, it is also easier to remember and execute the alg that way once you get used to it

so [R' D R, U2] y stands for R' D R U2 R' D' R U2 y
and [x'; R' D' R, U'] stands for x' R' D' R U' R' D R U x

I'm slowly getting into this notation and am by no means an expert, so sorry if I made any errors :)
 
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