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Blindsolving Accomplishment Thread

5BLD PB 22:42.505 (12:02.331) - Week 15 Scramble 1
Beat my previous PB by nearly 10 minutes!! (I've got so many DNFs recently that I've been going slow for all my solves)
But this time my sentences flowed really smoothly and there weren't too many breaks in cycles/sentences so my memo was much faster! And then during execution I was convinced that I did something wrong right back to X-centres but I persisted and ended up with a success! Yay!
 
It's been a pretty good day for PBs.

4BLD 4:41.93 [2:05.88] - PB by 2 seconds

1. 4:41.93 F2 Fw D F' B2 Uw2 B' F2 U2 B' Fw2 D2 R2 F' U D2 L Rw' U D' Uw L' Uw2 Rw2 U' B L2 Rw' F2 Rw L' D' B U' Rw D' Rw2 U Rw' B

Decent scramble
 
I finished writing out my +center comm list! Some of them are probably not the most efficient ways to do things, but 1. they're definitely better than some of the setup moves I was coming up with for "on the fly" comms and 2. now that I've finished one comm list, I have a lot more motivation to work on other piece types too.
 
The PBs are plentiful today! 3BLD 48.10 ao12 containing 43.30 ao5 and 42.05 mo3, all PB :)

2-6 are the 43.30 ao5, 3-5 are the 42.05 mo3.

avg of 12: 48.10

Time List:
1. 43.74 F U2 B' R2 F2 U2 F R2 B' R B' U R2 F' U R B' U2 R Rw Uw'
2. 50.17 F D2 B2 L' F2 B' R2 U' D2 L' B2 R2 D2 R F2 B2 L D2 F2 B' Rw' Uw2
3. (39.40) F D2 F2 D2 L' R' D2 L' U2 R' F R' B2 D U L2 B U2 L' Fw' Uw2
4. 41.09 D' R' L' F' L2 B' R F' D F2 D2 B2 R2 D2 R D2 B2 R F2 B2 Uw'
5. 45.65 D2 U2 B2 F2 L U2 L2 R2 F2 R2 B U2 R' F L' R2 D' F U B2 Rw2 Uw2
6. 43.14 B' U B2 R' U' B D2 B U B2 U' D2 B2 D F2 R2 F2 R Rw2 Uw'
7. 54.19 R2 B2 U2 L B2 F2 R B2 F2 D2 U F' D2 F2 D' L U' B' L R Uw
8. 56.12 D R U2 R2 F2 D2 B2 U2 L' U2 B2 L' D' L U F' U R U2 R2 Uw
9. 56.38 U2 F R F B' U R2 D B F2 R2 D' F2 U B2 D' B2 L2 Rw' Uw2
10. 48.19 L2 D2 R' B2 D2 U2 R B2 L F2 U B' U' B2 R' F R2 D2 L D2 Rw' Uw'
11. (57.78) F B2 R' D2 L U2 L2 B2 R U2 D R D2 R F U2 L F2 L' Fw' Uw2
12. 42.23 U2 L2 F U2 F' L2 F' R2 F2 L2 F U' R B2 U F2 R2 D B' D2 F2 Uw'
 
Not a standard accomplishment, but after over a year of blindsolving, I finally learned how the advanced parity method of memorizing the UB and UL edges swapped works. It seems like it won't take too long to get used to, and a really easy way to save about 7 moves per solve (on average), so I think I'll start using it from now on.
 
BenBergen said:
7 moves per solve (on average)
Click to expand...
25% scrambles you memorise one more letter and do the exact same
25% times you memorise one less letter and do one less cycle
50% scrambles are the exact same
thats nowhere near 7 moves less on average
im not saying it is bad, i personally dont like it, but mind that you are saving cycles only when the edges you are swapping are in the same cycle, at least i think thats how it works, you are sacrificing memo flow to get to do one cycle less 25% of the times
I think learning algs like D RU'R' U D R2 U' R' U R2 D2 or r2 U2 R' F R U2 r2 F L F' r' is a more natural step
 
Last edited by a moderator:
lucarubik said:
25% scrambles you memorise one more letter and do the exact same
25% times you memorise one less letter and do one less cycle
50% scrambles are the exact same
thats nowhere near 7 moves less on average
im not saying it is bad, i personally dont like it, but mind that you are saving cycles only when the edges you are swapping are in the same cycle, at least i think thats how it works, you are sacrificing memo flow to get to do one cycle less 25% of the times
I think learning algs like D RU'R' U D R2 U' R' U R2 D2 or r2 U2 R' F R U2 r2 F L F' r' is a more natural step
Click to expand...

Interesting, I just assumed that edges memo would always be one less cycle; I haven't toyed around with it enough to come across scrambled where it's one more than otherwise.

Thanks, I'll check those other options out.
 
BenBergen said:
Interesting, I just assumed that edges memo would always be one less cycle; I haven't toyed around with it enough to come across scrambled where it's one more than otherwise.

Thanks, I'll check those other options out.
Click to expand...
the way i solve parity is old pochman + UB UL (swapping them) First Edge, so i never memorize UL, couse its always UL, or LU, if its really convinient, to me having to memoroize one hanging letter is actually anoying, i have enough visual with twists
mark49152 said:
Which some might consider worthwhile for an event ranked by singles.
Click to expand...
well last time i compited it was, and i considered doing crazy stuff just to potentially get the WR (I got top 5, then just lost interest) but i wouldnt do it anymore, if you put it the other way around you have 25% chances of having to memorise one less letter, wich could end up in a wolrd record, not sure what are you implying, this is not one of those well your method is better but mine is easier so consdier that type of comment, thats bs, but having to swap the pieces in some scrambles and not in other might slow down your times, and not only your averages
but none of these were my point, my point is its not one cycle less for every parity scramble, only for half, for the other half is slightly worse, compared to my method
i think ben was getting it wrong
i really dont know what you are implying
It bothers me by the way
 
Last edited by a moderator:
lucarubik said:
25% scrambles you memorise one more letter and do the exact same
25% times you memorise one less letter and do one less cycle
50% scrambles are the exact same
Click to expand...
How did you arrive at these numbers?

lucarubik said:
the way i solve parity is old pochman + UB UL (swapping them)
Click to expand...
And what do you mean by "UB UL (swapping them)"? Do you memo them swapped, or do something like D' L2 D M2 D' L2 D to swap them?
 
pinser said:
How did you arrive at these numbers?


And what do you mean by "UB UL (swapping them)"? Do you memo them swapped, or do something like D' L2 D M2 D' L2 D to swap them?
Click to expand...
I make the cycle UB- UL- first edge, this swaps back UB and UL after old pochmann and solves the first edge
when you memo the edges swapped you are either joining them in the same cycle if they belong in 2 initally or separiting them in 2 cycles if they are initally in the same one
the fact that i use UB as buffer might have something to do with this, im not sure how people ussually use this D' L2 D, M2 algorithm, you do it before the edges and the first edge M2 style? thats ineficient as hell isnt it?
anyway if you do solve parity like i said above addinge those extra 7+4 moves you are still doing one less cycle half of the parity times, in substitution for those 11 moves, i believe it works like that, it defently works like that for my way to solve parity
 
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