BH Tutorial

[aronpm]

Could someone please post solutions to the exercises?
I found a 10 move commutator for the very first one, but I know it should be 8.

8 moves:
1) a) U'F'U B U'FU B'
b) L' URU' L UR'U'

2) R' ULU' R UL'U'
3) L'U2L D' L'U2L D

9moves:
1) F2 R' F' L2 F R F' L2 F'
2) U2 F' U B2 U' F U B2 U
3) U' R2 U' L' U R2 U' L U2

Orthogonals:
1) F R'D2R U R'D2R U' F'
2) F' RD2R' U' RD2R' U F
3) F' UL2U' R' UL2U' R F

Cyclic Shifts:
screw these, solve them by setting up to A9s, like columns.

Columns:
Protip: never set these up to cyclic shifts.
1) D' F2 D F U2 F' D' F U2 F D
2) R U L2 U R' U' L2 U R U2 R'
3) L' D2 L D R2 D' L' D R2 D L

Per Specials:
1) U2 L'U2RU2L U2 L'U2R'U2L
2) inverse of 1)
3) z2 U2 R'U2LU2R U2 R'U2L'U2R z2

 

[XXGeneration]

For something like URB FRU FUL, for example, could you use both F and F' as an interchange move?

 

[aronpm]

No. If you use F' there is no 3 move insertion to move UBR into FUL

 

[XXGeneration]

How can you tell if there is a 3 move insertion or not?
My biggest problem right now is just finding the 3 move insertion.

Edit: also, why doesn't something like LB2L' work as an insertion?

 

[Faz]

Edit: also, why doesn't something like LB2L' work as an insertion?

It does

 

[aronpm]

LB2L' doesn't work for that case.

Unless you want to do F2 LB2L' F LB2L' F

 

[XXGeneration]

It doesn't work when I try it. Why doesn't it work?

 

[StachuK1992]

For 'intuitive' BH edges similar to the BH corners here, is Chris' explanation on the other thread the best available currently?
I'd like to have some fun trying BH out.

 

[rock1313]

with the case URB FUR FLB I tried UF'U' F2 UFU' F2 but it didn't work why (I've also tried U2L'U2 R U2LU2 R' but that didn't work either)

 

[aronpm]

with the case URB FUR FLB I tried UF'U' F2 UFU' F2 but it didn't work why (I've also tried U2L'U2 R U2LU2 R' but that didn't work either)

I don't think that there's a FLB corner.

 

[Zane_C]

You want the interchange to be the R face. Without rotations it can be done as B L' B' R B L B' R'

 

[rock1313]

oh sorry I think it's FBL but im not sure

 

[rock1313]

don't bother finally found a solution

 

[aronpm]

don't bother finally found a solution

If you tell us the ACTUAL cycle, we can tell you the solution.

FLB is NOT a corner because that FLB means "front, left, back" and you can't have a corner with opposite colours.

 

[Zane_C]

Oh, I just looked back at it. For some reason I assumed FLB was LFU.

 

[rock1313]

sorry it's FLD isnt it

 

[RyanReese09]

Didn't feel like a new thread was appropriate. Plus it'll help others searching.

Also, how would I memo for BH when doing it in BLD?

 

[aronpm]

Give me 14 minutes of my life back. That question was not worth a 14 minute video.

"How do you know whether to do the insertion or the interchange first?"

There. It didn't take me 14 minutes to ask that.

As to the question, I won't answer solely because of the way you asked.

 

[RyanReese09]

Give me 14 minutes of my life back. That question was not worth a 14 minute video.

"How do you know whether to do the insertion or the interchange first?"

There. It didn't take me 14 minutes to ask that.

As to the question, I won't answer solely because of the way you asked.

Then thank you for the worthless post. My life has improved since I got to read that post.

And there were other questions there, aka questions on my logic of how to approach commutators.

 

[MrMoney]

Look at the cycle A -> B -> C (A the buffer goes to B goes to C goes to A)

Find out where both the interchange and insertion will happen (is it at A, B or C?).

If it is for example B, you need to move the piece that goes to B (A) first. If the interchange and insertion will happen at C, interchange/insert B to C first and follow standard ABA´B´.

If this does not make sense then shout out!