rubiksfriend
Member
Actually, I solve a 1x1x5 band, insert two outside 1x1x5 bands, then the remaining inner 1x1x5 centers.
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Erik gave me the idea of somewhat doing this. Instead of building 1x5 blocks, you just build the inner 3x3 block. Then you extend that block with a couple of 1x3s and then fill in the 2 outer 1x5s I've been using it and to a degree of success
Yep, you build the bar/line/row on another face and then attach it to the correct face. This doesn't work really well for the last 2 faces. It is basically done like in this video, only with 5 pieces instead of 3. There are no algs, only intuitionHi
I have read in many posts already about making those 1x1x5 bars. How is that done (in some detail). What i figure is that they are built on some other layer and then inserted. Does this still work with only 2 unsolved faces to solve ? etc ....
- Per
Yep, you build the bar/line/row on another face and then attach it to the correct face. This doesn't work really well for the last 2 faces. It is basically done like in this video, only with 5 pieces instead of 3. There are no algs, only intuitionHi
I have read in many posts already about making those 1x1x5 bars. How is that done (in some detail). What i figure is that they are built on some other layer and then inserted. Does this still work with only 2 unsolved faces to solve ? etc ....
- Per
[checker off]and i forgod an klosing brakket two. Its plane too si dad mine english sugs. im affraid i wil ceep makeing simular misstakes indefiantly.[chekker on][chegger on][checkker on][checker on] => auto-corrected to [/checker off]Arnaud: simular
I don't think this is "like" me. It is exactly how I described "bars/squares inside out" (unless you do the inner 3x3 differently).I'm doing it somewhat like you, first I build the inner 3x3 centers square like I'm used to from the 5x5 cube, then I add two opposite 1x3 center tredges, then the remaining two 1x5 blocks.
Off course it still works, just not as well as for the first 4 centers. For the first 4 centers it is just "position, move out of the way, restore". For the last 2 centers it is basically a commutator or another type of alg
Yes, I do the inner 3x3 differently. For example if these are U and F:I don't think this is "like" me. It is exactly how I described "bars/squares inside out" (unless you do the inner 3x3 differently).I'm doing it somewhat like you, first I build the inner 3x3 centers square like I'm used to from the 5x5 cube, then I add two opposite 1x3 center tredges, then the remaining two 1x5 blocks.
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It kinda wasn't, at least I didn't present it that way. Rather than typing this, I'd show it on video, but that might have to wait until after US Open. But it's not that special/hard anyway, is it?And I didn't understand your topic was about the last two centers. Could you give a scramble and a solution?
I've been doing this for over 1 year on gabbasoft's 7x7. I had the idea pretty early. And it doesn't show much promise. It's something to add to the arsenal, but the recognition is pretty tough even after I've practiced it for a long time. There are cases when the a center triple is already done, I can place using the "outer-5x5" route and that saves a lot of time.An idea to solve the 7x7 centers: Reduce to 5x5 centers.
Step 1) Build 3x3 centers on all sides like you would on a 5x5.
Step 2) Build "center tredges" like you'd build tredges on a 5x5.
Step 3) Solve centers like 5x5 centers.
Hope that's clear, and hope this hasn't been mentioned before. Well, I think it's good and I don't hear Per cursing, so that might be a good sign.
Edit to make it clearer: Steps 1+2 make the centers of each side look like this:
Code:ABBBC DEEEF DEEEF DEEEF GHHHI
Step 1 builds the E square, step 2 builds the B/D/H/F triples.
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