5x5x5 last edges

Spencerical

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Joined
Jul 6, 2008
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I can solve 2, 3, and 4 cubes pretty easily and I can solve the 5x5x5 pretty easily as well with one exception: I have trouble solving the last two sets of edges. What is the easiest way to solve these last two?
 
Even if more efficient, is every one of those algorithms necessary to know to move forward? It's hard to memorize what all of them do when I use each one 1/10 of the time -- but I'll try.
 
I only know 5 of those algs. And those 5 are basically what I need to know to solve the last 2 edges. For the rest of the cases, I apply an alg of the 5 know and it will turn that unknown case into one I know.
 
There is another method for solving edges that only requires 1 of those algorithms (parity-fix). I think it is called AVG ;)


I leared AVG today.:D

It requires very little look-ahead and pairs two edges at a time. (Semi-pairs?)

I prefer it over one edge at a time.
 
bigcubes.com has a different method that is about as fast. I don't know of any method that is faster.

Bigcubes.com is still the "standard" method.
Some people are using bigcubes.com for the first 8 tredges, then AVG for the final 8 semi-pairs / 4 tredges
AVG is relatively new and becoming more and more popular.

Erik Akkersdijk uses AVG, Dan Cohen uses Bigcubes. Both are top of the world.
 
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