4x4 beginner last layer

[Deleted member 36445]

I'll post here a simple method to solve k4 last layer without needing to learn a bunch of commutators

You will need sune variations for edge orientation, standard oll and pll, edge 3 cycles (intuitive) and edge 2 cycle (parity alg)

the good news is that you won't face oll parity! yay \o/

( but you will face an arguably worst type of pll parity but... yeah ;_; )

This may be questionable, pointless and inneficient, but I wanted to share because maybe someone would want to learn just because is simple or just for fun.

Ok so the method is basically those steps:

1. solve edges orientation
2. solve corners orientation
3. solve corners permutation
4. solve edges permutation
5. solve edges parity if needed

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Spoiler: edges orientation

You can solve two adjacent 4x4 edges by doing a fat sune if they are near the same corner

 Twizzle link 

r U R' U R U2 r'

The other adjacent unoriented edges, far from the same corner, can be solved with sune and left slice conjugate

 Twizzle link 

2L' R U R' U R U2 R' 2L

other case is when two unoriented edges are in the same slice
you solve it with a variation of the same oll on 3x3

 Twizzle link 

R U R' U' 2R U R U' r'

if two unoriented edges are side by side, solve the fat sune case mentioned above, do U2 and do fat sune again

 Twizzle link 

r U R' U R U2 r' U2 r U R' U R U2 r'

standard 3x3 eo just in case you need...

 Twizzle link 

3f R U R' U' 3f'

 Twizzle link 

F R U R' U' F'

 Twizzle link 

F R U R' U' F' 3f R U R' U' 3f'

This is all you need to solve any eo case.

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solve corners using what you know. you can orient and then permute or do COLL if you know the case

Spoiler: corners orientation

 Twizzle link 

R U R' U R U2 R'

 Twizzle link 

R U2 R' U' R U' R'

 Twizzle link 

R' U' R U' R' U R U' R' U2 R

 Twizzle link 

R U2 R2' U' R2 U' R2' U2 R

 Twizzle link 

R U R' U R U2 R2 U' R U' R' U2 R

 Twizzle link 

R2 D' R U' R' D R U R

 Twizzle link 

R' U' R' D' R U R' D R2

Spoiler: corner permutation

adjacent corner swap (t perm)

 Twizzle link 

R U R' U' R' F R2 U' R' U' R U R' F'

opposite corner swap (y perm)

 Twizzle link 

F R U' R' U' R U R' F' R U R' U' R' F R F'

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Spoiler: edges permutation

you can solve 3 cycles using simple insertions

right edges U perm cw

 Twizzle link 

2R' D 2R
U
2R' D' 2R
U
2R' D 2R
U2
2R' D' 2R

right edges U perm ccw

 Twizzle link 

2R' D' 2R
U'
2R' D 2R
U'
2R' D' 2R
U2
2R' D 2R

left edges U perm cw

 Twizzle link 

2L D 2L'
U
2L D' 2L'
U
2L D 2L'
U2
2L D' 2L'

left edges U perm ccw

 Twizzle link 

2L D 2L'
U'
2L D' 2L'
U'
2L D 2L'
U2
2L D' 2L'

standard 3x3 epll may be useful here

 Twizzle link 

M2 U' M2 U2 M2 U' M2

 Twizzle link 

R U R' U R' U' R2 U' R' U R' U R

 Twizzle link 

R' U R' U' R' U' R' U R U R2

 Twizzle link 

M' U' M2 U' M2 U' M' U2 M2

(you may have to combine those algs to solve all the edges)

---

continuation...

SUFFER

Spoiler: edges permutation parity

this is the worst case of this method. sadj
parity 1

 Twizzle link 

2R U2 2R' U2 2R' U2 2L U2 2R' U2 2R U2 F2 2R2 F2 2L'

Spoiler: a somewhat easier way to solve...

You can solve it intuitively by making a single slice turn then solving the rest.

This is my intuitive way of solving that 2 cycle:

 Twizzle link 

2R // PARITY FIX
U2 2R U2 2R2 U2 2R x F2 2R F2 2R' x' // SOLVE CENTERS
U R B' D (F B') L' B L' (F' B) D R' U // SOLVE 3X3

for the 3x3 part I used cube explorer

explanation:

parity 2

 Twizzle link 

2R2 U2 2R2 Uw2 2R2 Uw2 U2

if those cases are adjacent you may do a conjugate with sexy move to make them adjacent

 Twizzle link 

R U R' U'
2R2 U2 2R2 Uw2 2R2 Uw2 U2
U R U' R'

 Twizzle link 

R U R' U'
2R U2 2R' U2 2R' U2 2L U2 2R' U2 2R U2 F2 2R2 F2 2L'
U R U' R'

Cube is solved!

EXAMPLE SOLVE

 Twizzle link 

 Setup 

L' Uw' D2 F' L' U B R Fw F' U' Rw F U F Rw U2 L2 Fw R' D U R Uw2 D2 F2 Fw Rw' Uw2 R Rw2 B2 Rw2 U2 R F2 Uw Fw U' Rw2

 Moves 

// CENTERS

y2 Rw Uw2 U' Fw z U' Lw' U' Lw // YW
z' x' U2 F' Rw' F Rw // R
Lw U' Lw' Rw2 U2 Rw2 // G
x2 F Lw F' Lw2' U2 Lw //BO

// XCROSS

z Fw2 L U2 L' U2 Fw2 // B
Rw' L' U L U' Rw // R
B L D' // SOLVE RB
y' L F' L' Uw L' U' L Uw' // O
U2 F' Rw' U' R2 U 2r // G
y D U R2 U F' 3u' R' U2 R // SOLVE OG + OG PAIR

// F3L
L' U L U' Rw L U' L' U Rw' D L' U L D' // BR PAIR
U' Lw' U' L U 2L U D R U' R' D' // GR PAIR
R' F R F' U' Rw U R' U' 2R' U2 R U R' U2 R U R' // GO PAIR

// EOLL
U Rw U R' U R U2 Rw' // 2 NEAR
U 2L' R U R' U R U2 R' 2L // 2 AWAY

// OCLL
U2 R' U' R U' R' U2 R // BACK SUNE

// PLL
(L U' L' U) r U2 r' U2 r' U2 l U2 r' U2 r U2 F2 r2 F2 l' (U L U L') // PAIR EDGES
U2 L U2' L' U2' L F' L' U' L U L F L2' // PLL (Ra)

 

[Cuber Score]

For people like me who don't feel like reading that entire thing:

Solve it like a 3x3 with parity algs if need be.

 

[fdskljgrie]

thank you for this! this is very helpful, especially parity 1

 

[Deleted member 36445]

thank you for this! this is very helpful, especially parity 1

Glad you liked
Tomorrow I'll post the way I solve parity 1 intuitively
I never learned that alg
I just do something i learned on jperm and solve parity with one move then i reconstruct what was broken, the same way every time
It's an easier way to remember for me but lots of moves lol (10 more than the alg, but easy to figure out)

 

[Deleted member 36445]

I updated the original post with an intuitive way to solve parity, and an example solve.

 

[OldSwiss]

What is the advantage of this method over just using the normal 3x3 method, every beginner already knows and then learing the 2 long but easy parity algs?

I counted around 20 algs in your method. That may not be very beginner friendly

But cool that you try to invent your own method

 

[Deleted member 36445]

What is the advantage of this method over just using the normal 3x3 method, every beginner already knows and then learing the 2 long but easy parity algs?

I counted around 20 algs in your method. That may not be very beginner friendly

But cool that you try to invent your own method

I sincerely think there is no advantage at all

BUT

You can think as a beginner K4 method, that uses algs most CFOPers already know

 

[fdskljgrie]

if two unoriented edges are side by side, solve the fat sune case mentioned above, do U2 and do fat sune again

 Twizzle link 

r U R' U R U2 r' U2 r U R' U R U2 r'

For this case, do you know an alg that won't change the way the corners are oriented?

 

[Deleted member 36445]

For this case, do you know an alg that won't change the way the corners are oriented?

just a combination of 2 3-cycles of edges. it won't affect corners.

 Twizzle link 

 Setup 

r U2' R' U' R U' r' U2' r U2' R' U' R U' r'

 Moves 

U' R U R' U' 2R U R U' 3Rw' R' U' R U 2L' U' R' U R