3x3x3 Rubik's cube permutations

[SLAVKO4996]

This is the old formula to calculate the Rubic's cube permutations:

(8! x 3^8 x 12! x 2^12) / 12=43.252.003.274.489.856.000

:fp

My new formula that is correct is:

((8! x 3^8 x 12! x 2^12) / 12) x 4^6=216.087.008.359.351.320.576.000

:tu

My name is Slavko Zupančič from Slovenia and I have invented this formula for the Rubic's cube that is correct and it is now published.
Thank you very much.

 

[ottozing]

You're wrong.

 

[JasonK]

Okay

 

[qqwref]

I can see what you were trying to do, but your formula is wrong. There are only (4^6)/2 possible center positions.

Edit: Also, I might as well mention that I'm pretty sure the formula you "invented" was already known in the 1980s. It is pretty basic.

 

[Litz]

Too much knowledge.

 

[cuBerBruce]

At a minimum, one should ensure the left hand side agrees with the right hand side.

 

[Noahaha]

3x3x3 Rubic's cube permutations:

I usually try not to be too pedantic but...

 

[Christopher Mowla]

Calculating Permutations on the nxnxn Rubik's Cube (See Post #19, if this link doesn't bring you to it).