2x2

[pjk]

How do I solve this thing?

 

[CraigBouchard]

Think about corners on a 3x3...and u might figure it out

 

[pjk]

Haha, that doesnt work too well for me, since on the top corners of a 3x3 I permute, and I can do that on the 2x2. Any other ideas?

 

[Scott]

There is a solution for the 2x2 in the beginner solutions thread.

 

[Harris Chan]

I want a speedcubing method...lol

 

[dougreed]

Well, solving 4 adjacent corners (equivalent to 3x3x3 first-layer corners) is easy enough. After that, you can use 3x3x3 algs to orient and permute the last four corners.

-Doug

 

[pjgat09]

I think of it as a 3x3x3 without edges. Imagine you have already solved cross, and you are now doing F2L, but without edges. Then orient the last layer, but ignore the non-existant edges. Then permute with a 3 cycle or y-perm.

Thats what I do, but its not very fast. If you want to get faster, try learning CLL (
http://www.speedcubing.com/final_layer_corners.html) or CMLL (http://grrroux.free.fr/method/Step_3.html).