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  1. Miro

    [Official] Feliks Zemdegs - 4.75 3x3 single

    Good joke, Feliks ;)
  2. Miro

    Red Bull Rubik's Cube World Championships

    Why WCA denied cooperate with RSA? Can someone write relevant info?
  3. Miro

    All top 10 3x3 singles are now sub 5

    Yes, actually 11: https://www.worldcubeassociation.org/results/events.php?eventId=333&regionId=&years=&show=100%2BResults&single=Single
  4. Miro

    Corn.E.Midge - Corners First, Made Easy and with Few Moves!

    Thanks for explanation, I agree with it. Sheet is nice :-)
  5. Miro

    Corn.E.Midge - Corners First, Made Easy and with Few Moves!

    I think, it is very similar to this one: http://rubikscube.info/ortega.php
  6. Miro

    HD Method (2x2, alternative to CLL+)

    Thank you, this document is ok. I have one outdated, maybe.
  7. Miro

    HD Method (2x2, alternative to CLL+)

    Hi, thank you for very interesting method. I think in LOLS- algorithm set is error. Case 3 and 6 are the same (Sledgehammer). And there missing mirror case with one yellow/white sticker on top, two yellow/white stickers on some side and yellow/white sticker on other side.
  8. Miro

    MagLev Tensions - DIY Tutorial ?

    Text from YT video about maglev: "This means when you're turning accurately, the tension will be lower, so the cube is FASTER, but when you start to mess up a turn and flex the cube, the tension is higher, so the cube is MORE STABLE."
  9. Miro

    One-Answer 3x3x3 Question Thread

    In my first question I asked for like-Uperm algorithm, which not prevent corners permutation. So maybe 3-gen algorithm which not prevent corners permutation is easier than Uperm, which prevent corners permutation. But Cube Explorer say there is nothing better than Uperm.
  10. Miro

    One-Answer 3x3x3 Question Thread

    For me nothing, but for totally beginners is maybe little complex :-)
  11. Miro

    Full LMCF 3x3 method now available

    What's about algorithms for L5E, which solve whole rest of cube? Solving UR edge + Midges orientation + Midges permutation with one algorithm. If I am not wrong and UR edge is on M-slice it is 88 new cases + mirrors. (If UR edge is flipped on own position, it is another 88.)
  12. Miro

    One-Answer 3x3x3 Question Thread

    Thank you for answer. I want to preserve corners orientation. I want to find easy one 3-gen algorithm<RUF>, not fast one.
  13. Miro

    One-Answer 3x3x3 Question Thread

    Where can I find algorithm similar to U-perm, which NOT prevents LL corners permutations? I think it should be easer and more suitable for beginner method. How can I generate it in Cube Explorer or some else software?
  14. Miro

    The WaterRoux 3x3 method thread

    I think viable is only EG1-style second block (partly second block). First block is fully solved, and second block has oriented, but swapped two corners (DFR, DBR). Recognition for CMLL and EG1-style is the same.
  15. Miro

    The New Method / Substep / Concept Idea Thread

    Another idea for this method: 2. Solve square on DR + corner, with swapped corners (RFD, RBD) 3. Solve last 6 corners with EG1-style 4. Solve L7E (ordinary LSE slots + FR) This way you can implement EG2-style too. EG0, 1, 2 have better recognition than TCLL. But stranger second, or both...
  16. Miro

    1-look 2-algorithms OLL on 3x3

    It is transition between 2-look an 1-look OLL. Maybe it is obvious, but it is not well known, I think. Most used algorithms for doing first step in 2-look OLL orient edges, but corners too. (F R U R' U' F', F U R U' R' F', F R U R' U' F' f R U R' U' f'). So predict second step in 2-look OLL is...
  17. Miro

    Making a Magnetic Valk 3

    I did one myself with N35 4x2mm magnets. My problem was that cube turns harder than I suppose. Screws on springs was unscrewed to maximum. So I try change springs, but no one works well, because Valk3 has special shape springs. After then I try cut one circle from original springs from their...
  18. Miro

    Full LMCF 3x3 method now available

    I cannot find in your PDF algorithms for orienting M-slice edges, if all R-edges and L-edges are solved. How do you realize this case? Unsolve one edge?
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