fanwuq
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This may already exist, but it is not regular 3-cycle.
Let's try this.
Suppose I memorize edges using letters for each position and if the edges is wrong, I come up with a word with bad connotation; and if it is correct, I come up word with bad connotation. (word maybe noun, adj, adv, verb, etc...) Memorize the edges using a few sentences. Then I just do the cycles as usual.
However, if I know the edge is wrongly flipped, I do the wrong set up for the particular edge, if the edge is right, I do the right set up for the particular edge. Then I do U perm and reverse set up.
Example UF to UR to RF, where UR and UF are correct and RF and UR is wrong. I can just set up as F' and do U perm then F. That would solve every thing?
Would this work? Or would this be too confusing?
Perhaps another alternative is to just do the regular OLL cases that Flip 2 Edges and cycles them.
But then, the trouble is : What if for that certain cycle, only one edge is wrong? Would that be remembered and ignored until the end as a parity?
Is this method like M2 and TurBO, or something? I did not really understand them (actually, I'm just too lazy to read the whole method), but they do seem to do edges in one step.
Let's try this.
Suppose I memorize edges using letters for each position and if the edges is wrong, I come up with a word with bad connotation; and if it is correct, I come up word with bad connotation. (word maybe noun, adj, adv, verb, etc...) Memorize the edges using a few sentences. Then I just do the cycles as usual.
However, if I know the edge is wrongly flipped, I do the wrong set up for the particular edge, if the edge is right, I do the right set up for the particular edge. Then I do U perm and reverse set up.
Example UF to UR to RF, where UR and UF are correct and RF and UR is wrong. I can just set up as F' and do U perm then F. That would solve every thing?
Would this work? Or would this be too confusing?
Perhaps another alternative is to just do the regular OLL cases that Flip 2 Edges and cycles them.
But then, the trouble is : What if for that certain cycle, only one edge is wrong? Would that be remembered and ignored until the end as a parity?
Is this method like M2 and TurBO, or something? I did not really understand them (actually, I'm just too lazy to read the whole method), but they do seem to do edges in one step.