OSPA(New 2x2 Method)

So it's like Guimond, but with the last two steps done with one algorithm... It'll probably make solving with one-look easier than in regular Guimond, but probably not as good as in EG/CLL. And considering there were some Sub-3 averages with regular Guimond, it may be fast.
If I understood the description of the method.
 
Can you give here a list of the algs that should be changed from SOAP algs to OOC algs?

BTW, for this case:
setup: R U2 R' U2 R U R' can be solved with F' U' F
 
Hmm, it's an interesting idea. However I feel it's a step backwards. If you took this method you could make the final step Alg count and recognition a lot better by doing 0-2 premoves at the start of the solve... Which is soap.
 
emolover said:
Very likely faster and is only two steps instead of four.
Click to expand...


The first "step" takes like 0.1 moves per average or something silly like that. The number of steps is pretty uninteresting, but rather how often a method produces 1-look solutions, which I'd think EG does way more often due to its short first step.
 
emolover said:
Same thing I told PandaCuber, see if you can make up some good OOC algs(orient opposite color) that are efficient and easy to execute. Does not have to be 2gen but can be 3gen using LUR or RUF.

Also if you find a good 2x2 solving program, that would be wonderful.
Click to expand...

Do you mean the same as in this link and only better algs? Beacuse there are already all algs. Or do you mean the second step?

edit: I am also having another question. How many possible cases are there for the second step?
 
Last edited:
OK I think I understood what you mean.

1. F R F' R' or F R F' R
2. F' U F
3. U' R U R'
4. U' R (F R F' R)
5. U2 R U' (F R F' R)
6.
7. R U2 F' U F
8. R U' R D' R' D' R'

Here are some other algs for the column to left. I don't know if the algs are really good, but many of them are at least shorter.

Couldn't find a good alg for case 6!

What do you think?
 
The main trick to this method would be the last step, which is the pbl+separation algs.
I think this method is potentially easier to 1-look than eg but it all depends on that critical last step.

You need to get a list of the actual cases, to prove its not actually some absurd number, and also come up with a recognition method.
 
Yes you are right that I need to do some work on the method but I couldn't today because I was feeling really down and I am working on something else for cubing as I work on this method.
 
Algs for the 3-1 permutation cases

I think I have found most of the 3-1 permutation cases. 23


Case 1-8
U R2 U R2' U' R2 U' R2'
U'F2UR2U'F2
R'FRU2F2R2UFU'R
UF2UR2U'F2UR2U2
F2R'U'RF2R'UR
U2F'UR'U'FU2FRFR'
R2UR2U'R2U
R2UR2U'R2U'


Those cases are used if there are one solved layer (except the piece in opposite colour) at the bottom layer.

Case 9-16
Haven't done any algs. But it is the same cases as above but at the U-layer

Case 17-20
FRUF'U2F'R'U'FR2U' (DFL-UFR-UFL-DFR)
FRFU'F2U'R'U'RF2U (DFR-UFL-UFR-DFL)
y'RURUR'UR'U'RU'(DFR-UFR-UFL-DFL)
y'R'U'R'U'RU'RUR'U(DFL-UFL-UFR-DFR)

Those cases are used if there are two 2x1 block solved at UB & DB

Case 21-24
FR'U2F2R'U'RF2U'FU (DBR-DBL-DFR-UFR-UBR)
FUFU2F2R2FU'FU2 (DBR-DFL-DFR-UFL-UFR)
FURF2U2R2U2R'U'FU2 (UFR-UBR-UFL-DFR-DFL)
FU'F2R2U'F'RF2U'RU (UFR-UFL-UBR-DBR-DFR)

Those cases is hard to see what they are doing.

Case 25-28
FURU'FR2FRU2F'R (UBR-UFL-DFR-DFL)
FUFR'FU2FUR2F'R (DBL-DFR-UFL-UFR)
U'F2U'F2UR2F2U2 (DBL-DFR-UFR-UFL)
U'F2R2UR2UR2U2R2 (UBR-UFL-DFL-DFR)

Cases if there are one 2x1 block solved at one layer and a Y-perm at the other layer.

Case 29-32
FUF'RU'FU2F'R'U2R2 (T-perm DL & UL+UFR-DBR)
FU'FR2URF2R'U'RF2 (Y-perm(UFL-UBR & DFR-DBL)+UFR-DBR)
FRFR'URF2RU2F2R2 (T-perm UL& Y-perm DFR-DBL)
FURU'RFU2FU2R2F2 (T-perm DL & Y-perm UFR-DBL)


Case 33
U R U' R' U' R2 F2 U' R U R

Last alg, couldn't find any similar.
 
Last edited:
Also wanted to post some algs for the orientation step. This site will help you to see which situation it is. Cases in "[]" aren't changed beacuse they are pretty nice or beacuse I couldn't find any nice algs.

All algs aren't nice, but some of them really are!

1. F R F' R' or F R F' R
2. F' U F
3. U' R U R'
4. U' R (F R F' R)
5. U2 R U' (F R F' R)
6.* [R U' R' U R U'R']
7. R U2 F' U F
8. R U' R D' R' D' R'

1. F R U' R' or F R U' R
2. R U' R
3. U' F' U' F
4. [R U R' U' R U R']
5. U F' U' F R U' R
6. [y' R' U R U' R' U R]
7. U F' U2 R U' R
8. [R U2 R U' R U2 R]

1. R' F R2 F' U'
2. R F' U2 F
3. [R' U R2 U' R]
4. [R' U' R2 U' R2 U' R']
5. R2 F R2 F
6. [R2 U' R2 U2 R']
7. [R' F R F' R' U R']

1. F U2 F R F' R
2. R' U' F R U' R'
3. y F U2 F R U' R'
4. [R U2 R' U2 R U2 R' U2 R]
5. R
6. y F U' F R U' R'
7. R' U' R U' R

1. F D' F'
2. [x R U R' U' R U R' U']
3. U' R' D2 F' U L'
4. [R U' F R F']
5. [R2 U R' F R2 F']
6. [R U R' U2 R]
7. [R' U R' U R']
8. L' U' L U2 R U' R [R' U' R2 U' R' U' R2]

1. U' y2 F' D F
2. [x U R U' R' U R U' R']
3. y U' F D2 R D' R'
4. [R' D' R' U' R]
5. [F R2 F' R U' R2]
6. [R' U2 R U' R']
7. [R U' R U' R]
8. [R U R U2 R U R]
 
Added 2 cases which I had missed (27&28)


I have also realized that you often can choose between 2-3 cases in the orientation part. That means that you very often can do a short case and it will be much easier to 1-look.
 
So wait, how many of the Separate-Permute algs still have to be found? I might try to help. I'm really looking forward to being able to use this method in full :)

EDIT : @emolover : Those links aren't working for me.
 
This method reminds me soo much of some algs I found 3-4 years ago.

I used to call is Guimond2 I think.

Ill try to find the cases tomorrow (after Super Bowl and sleep)

I do not promise that the algs are good (at all)
But I think that I had an idea of recognition.

Something with, do you get a bar in bottom layer or will the one piece over it make a bar with one of the ones just below. (can be seen by opposite colors)
and basically the same for top layer.
I have no idea if the idea works since I have not gotten around to learning them all.
 
It is hard to say how many cases there are, but I think those 33 are more than the half at least.
When I was playing around with this method yesterday, I got one of those L-cases in about 60-70% of the solves.

It doesn't mean that it is more than the half algs, but it might be.
 
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