What method do you use for 4x4

What method do you use for speedsolving the rubiks revenge

  • Reduction

    Votes: 124 69.3%
  • Yau

    Votes: 29 16.2%
  • Akimoto

    Votes: 0 0.0%
  • K4

    Votes: 10 5.6%
  • Cage

    Votes: 0 0.0%
  • Sandwich

    Votes: 2 1.1%
  • Z4

    Votes: 3 1.7%
  • KBCM

    Votes: 1 0.6%
  • Any other(please specify)

    Votes: 10 5.6%

  • Total voters
    179
What exactly is the difference between regular Reduction and Yau?

I use reduction with double edge pairing. My 3x3 LL is a joke though. It can take 20+ seconds. PLL is terrible.
 
Redux with 2-2-2-2-2-2 pairing, which by chance occasionally ends up being 3-2-2-2-3 or 3-2-2-3-2 or 3-2-3-2-2 or 3-3-2-2-2 or 2-3-3-2-2 or 2-3-2-3-2 or 2-3-2-2-3 or 2-2-3-3-2 or 2-2-3-2-3 or 2-2-2-3-3 or if an edge pair is already solved then it is 2-2-2-2-3 which by chance is instead sometimes 2-2-2-3-2 or 2-2-3-2-2 or 2-3-2-2-2 or 3-2-2-2-2.

EDIT: wait, no. That is not the answer to the poll. Just actually read the question. I never speedsolve the Rubik's Revenge. But when I speedsolve the Maru 4x4, I use the above-mentioned method.
 
Yau, normally 3-3-2 but it all depends on the case you run into.
In Yau, I'm pretty sure you build a cross before pairing the other edges.
Opposite centres, 3 cross edges, remaining centres, finish cross, remaining edges, finish the rest.
 
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btw. yau method doesn't exist. dankoen lied to us.

its effing meyer method. kthxbai

And I do waffo redux. which is like "NOT yau"

Sure, you're technically right, but did Meyer propose the same way as I did or as Dan did for solving the last cross dedge + the remaining 8 dedges?

I'm just saying surely Dan and/or I deserve some credit...
 
Sure, you're technically right, but did Meyer propose the same way as I did or as Dan did for solving the last cross dedge + the remaining 8 dedges?

I'm just saying surely Dan and/or I deserve some credit...

yes, you do, because your method of reducing the cube causes a lot of 'good' things to happen.
things i like about yau:
1. you're building the cross while you pair edges, so no random inspection after reduction.
2. you integrate syuhei's edges, but eliminate the D face giving better lookahead
3. the first edges you pair are cross edges, giving you the lookahead advantage by 'blocking out' distractions of possible pairs
4. typically when you're 6 pairing the final edges, the bad cases are quickly noticed, quickly solved.
5. a lot of good stuff happens with this method
 
Stadler - recognition of edge pairing is quite easy

Somtimes I just put accidently solved edge in the second roux block and switch over to petrus for final assemblement.
 
Using a lazy-man's K4 =P

My typical solve goes:
6 - ½ - ½ - 1½ - ½ - 3
 
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Redux with 2-2-2-2-2-2 pairing, which by chance occasionally ends up being 3-2-2-2-3 or 3-2-2-3-2 or 3-2-3-2-2 or 3-3-2-2-2 or 2-3-3-2-2 or 2-3-2-3-2 or 2-3-2-2-3 or 2-2-3-3-2 or 2-2-3-2-3 or 2-2-2-3-3 or if an edge pair is already solved then it is 2-2-2-2-3 which by chance is instead sometimes 2-2-2-3-2 or 2-2-3-2-2 or 2-3-2-2-2 or 3-2-2-2-2.

I lol'd
 
I made my own weird method where i solve the centers, make 4 edge pairs for the bottom cross insert the corners, pair th edges while i use the beginner's method to solve the "2nd layer" (really 2nd and 3nd) then i do random trial and error to solve the top layer's edges then solve the top layer, if you understood that...
So basically your own shitty version of K4 then? I mean randomly solving LL edges? Get to know comma and it will be a lot easier.
 
6lyio.png
 
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