Rpotts
Veteran
ubercuber, stfu. it's the internet.
Cincy
Cincy
uberCuber
Legend
ubercuber, stfu. it's the internet.
So, it's the internet..what does that have to do with you misreading what he wrote? I do not believe it is any more difficult to read on the internet than anywhere else.
Sigh, you guys should really pay atttention in math. Multiplying the number of oll algs by the number of pll algs will result in the amount of cases you can apply 1 look ll. However, you guys want the number of algs you need to learn, and to get to such it's: The number of oll algs plus the number of pll algs which will equal the number of total algs you need to learn. I really don't get why you'd multiply.
Most of my non-bld solves are one look as well
Frank Morris can solve the cube in -1 looks.
Edit:
What? You WOULD have to multiply. You ADD for 2LLL. MULTIPLY for 1LLL.y3k9 said:
But guys...I'm not sure if I am right on this, but wouldn't there be alot more than ~1100 cases? Because if you need to do something like this:
Sune OLL, U2, T Perm to solve a 2LLL case,
Sune OLL, T Perm would not work for a 1LLL case, because you miss the U2 inbetween, ending up not solving the cube.
So this means for 1 OLL and 1 PLL, you would need to learn 4 algs.
For example,
1. Sune OLL+T Perm
2. Sune OLL+U+T Perm
3. Sune OLL+U2+T Perm
4. Sune OLL+U'+T Perm
This would quadrouple the amount of algs needed to learn, making it ~4400 algs.
Please correct me if I am wrong.
Edit 2:
I just remembered some PLLs like H Perm can be solved without AUFing, because the alg still works (E Perm also can solve 2/4 states, and other PLLs I'm too lazy to think of).
So, there would not be 4400 algs, but there would still be alot more than 1100 algs.
Last edited:
somerandomkidmike
Veteran
ZBF2L uses 125 algorithms. Also, I'm not going to claim I know what I'm talking about. I don't use LBL methods at all. You're probably right that recognition would be terrible, but at least this way you would only have to look at the OC and PC.
Kirjava
Colourful
You're just annoyed that people laughed at you because you made a topic where you didn't understand how to solve corners on a 4x4x4.
cincyaviation
Veteran
It definitely could be done, but it would take a lot of work to make it decent, and it would probably take longer than just OLL/PLL. And also, i believe it would be less than 42 corner algs because not all of the COLL cases are possible with edges solved.
somerandomkidmike
Veteran
Well I was asking if that would be a reasonable option, not stating that it was. However, I've found the 42 cases: http://www.ai.univ-paris8.fr/~bh/cube/solutions_c2.html
Also, ZB takes longer than just OLL/PLL, so I'm not surprised that this would.
Rpotts
Veteran
JESUS CHRIST USE SOME GOD DAMN SUNES
cubefan4848
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Feliks used ZBLL in a 7.09 solve he did. So it can be faster at some times but definitely not all the time
irontwig
Veteran
Sure it wasn't just a COLL and the EPLL skip?
FatBoyXPC
Veteran
Isn't ZBLL just a possible extension of COLL?
irontwig
Veteran
Never mind, saw it now, it's a 9 move Y-perm, bïtches.
somerandomkidmike
Veteran
Of course there are cases that could be faster. Recognition generally isn't great though. Also every case in the LL layer approach I've posted appears in ZBLL.
cubernya
Premium Member
You do realise not a single person in the world has memorized every case for 1L-LL
emolover
Legend
How do you know that? There very well could have been someone who has memorized full LL. If like 5 have memorized full 493? ZBLL algorithms than I am sure at least one person has had balls to memorized all 1293? LL algorithms.
uberCuber
Legend
I am curious how the number could be this low. There are 42 CLL cases. Giving the CLL case a fixed orientation, there are 8 cases for edge orientation, and 12 cases for edge permutation. 42 * 8 * 12 is a lot more than 1293. Obviously mirrors reduce the number quite a bit, but I still don't see how the number could be as low as 1300.
EDIT: Oh, unless inverses are counted as the same alg as well? Then I guess that number actually sounds reasonable
RyanReese09
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IIRC at nationals last year, some guy was up at like 800 or so algs. Learning move optimal purely for FMC (I'd assume FMC)
kinch2002
Premium Member
And was he any good at FMC?
nlCuber22
Veteran
Was it Chris Tran? I don't think so.. I know Morley Davidson knew (knows probably) full ZBLL.