Sandbox

<object width="560" height="340"><param name="movie" value="http://www.youtube.com/v/3kJjeRpPtY0?fs=1&amp;hl=en_US&amp;rel=0"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/3kJjeRpPtY0?fs=1&amp;hl=en_US&amp;rel=0" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="560" height="340"></embed></object>

Edit: That's a fail. How do I embed youtube videos?

You may want to read the sticky that is called Please Read Prior To Posting Videos .

WB pictures?
http://www.tinypic.com
 
Just put your mouse over it.. but I guess you already know because you are reading this.. or maybe you are quoting it.. but now you know.. your welcome...
 
Testing Math Tag

\( ((\frac{1}{2})(x+y))^2-((\frac{1}{2})(x-y))^2 \)
The mean of x and y, squared, minus the the distance from the mean of x and y, squared.

= \( [\frac{1}{4} (x+y)^2] - [\frac {1}{4} (x-y)^2] \)
By squaring \( \frac{1}{2} \) on both occasions.

= \( [\frac{x^2+2xy+y^2}{4}] - [\frac{x^2-2xy+y^2}{4}] \)
By distribution.

= \( \frac{x^2}{4} + \frac{xy}{2} + \frac{y^2}{4} - \frac{x^2}{4} + \frac{xy}{2} - \frac{y^2}{4} \)
By separating terms.

= \( \frac{2xy}{2} \)
By cancelling, by simplifying like terms.

= \( xy \)
By simplifying, by dividing by \( \frac{2}{2} \)

Thus proves that for any two given numbers x and y,
xy equals the square of the mean of x and y, minus the square of the distance from the mean of x and y.
 
TESTING ITALICS AND BOLDNESS AND UNDERLINING AND capital letters AND ALSO CHANGING SIZES.
 








So I can't apply algs to bigger cubes?

I thought no cube with a higher order than 6x6x6 was possible without larger outer layers.
 
Last edited:
Rubik_cube.png


Testing out a new AJAX image resizer.
 
Back
Top