Pyraminx Crystal Edge Parity?

some1rational

Regular
Joined
May 4, 2010
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28
Hey guys, I just got my pyraminx crystal today and am in the process of solving it.

However, as I was solving it, two edge pieces fell out and I didn't know which one went where when i put it back together (put it back together partially solved)

Now I'm at the very end and I only have two edges swapped (everything correctly oriented); I just wanted to know if this is because I put it in wrong accidentally when I put it back together or is there really a way to have just two edge pieces SWITCHED with the rest of the puzzle solved

I'm pretty sure its not possible and I just switched them accidentally when putting the puzzle back together (since I can only find commutator algorithms that do 3-cycles of edges) but I just want to make sure here
 
If the puzzle has 12 colours (which I'm pretty sure it does) then no, it is because it popped and you assembled it incorrectly.
 
haha thanks guys,

I wasn't confident enough in my own intuition and logic to gauge whether or not it was actually possible haha, good thing because I wasn't able to figure out a move that could do it

EDIT: wait, can someone explain why it does FOUR 5-cycles? I can see that there are '2' sets of 5 edges and one set of 5 corners...so wouldn't that be three 5-cycles for one turn? and what exactly is a middle layer turn in this case? it seems there's only one way to turn the pyraminx crystal

also, (one more question, haha) can someone briefly explain why it cannot change the parity given the number of 5-cycles? sorry just got into the whole puzzle craze but I'm enjoying it lol
 
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EDIT: wait, can someone explain why it does FOUR 5-cycles? I can see that there are '2' sets of 5 edges and one set of 5 corners...so wouldn't that be three 5-cycles for one turn? and what exactly is a middle layer turn in this case? it seems there's only one way to turn the pyraminx crystal

Yeah I'm confused about this too (probably because I don't have a pyra crystal >_>)

also, (one more question, haha) can someone briefly explain why it cannot change the parity given the number of 5-cycles? sorry just got into the whole puzzle craze but I'm enjoying it lol

It actually doesn't really matter how many 5-cycles there are :p
It just matters that all 5-cycles are even permutations (it's like swapping pairs of edges 4 times, which is an even number of swaps)
 
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