VHF2L+2 Levels=F2l+OLL Skip

[BatafCube]

So i was plaing with VHF2L(only the cases where the 2 f2l pieces are paired up) and i got a OLL skip and then this idea came to my head.Why doesn't some1 make a list of F2L algorithm where the f2l pair is paired(so much less cases) and does a OLL at the same time?I call it VHF2L+2 levels.Because VHF2L+1 level=ZBF2L.

I am going to show you whit a solve:
Scramble:R U R' U' R' F R2 U' R' U' R U R2 F' R U R U R' U2
Look how the F2L pair is paired.Now do EO+CO at the same time+solving F2L.
Solve:U2 R U' R' U' R' F R F'
You have a forced OLL skip.And then just the PLL (

The number of Algs will be 54(the number of WV)*8(the number of VHF2L)=432 algs.Only with 130 algs more then ZBF2L,but this new F2L strategy+PLL(453) is still less then Full ZB(800).

What do you think for this idea?

 

[miniGOINGS]

Well, you still have to pair up the corner and edge.

 

[BatafCube]

Well, you still have to pair up the corner and edge.

So?That is done in 1-2 sec MAX.

 

[miniGOINGS]

Well, you still have to pair up the corner and edge.

So?That is done in 1-2 sec MAX.

Yea, but for only a couple of moves you could solve the entire F2L. That's like 0.5 seconds MAX.

 

[BatafCube]

Well, you still have to pair up the corner and edge.

So?That is done in 1-2 sec MAX.

Yea, but for only a couple of moves you could solve the entire F2L. That's like 0.5 seconds MAX.

Yes,but now OLL skip

 

[miniGOINGS]

And how is recog going to be?

 

[BatafCube]

The beginning of the scramble is a T Perm with the last R' as an R2.

The important thing is to get the right idea

 

[BatafCube]

And how is recog going to be?

Well recognie first the VH/WV then WV/VH.Just like in ZBLL first COLL then the EP.

 

[4Chan]

54 algs for WV?
I thought it was 27. d:

This idea seems familiar, as if someone has thought of it before.
My intuition is telling me that your numbers are off. Also, by a wide margin.

 

[miniGOINGS]

Yea, I was joking about the grammer thing. You caught me.

And how is recog going to be?

Well recognie first the VH/WV then WV/VH.Just like in ZBLL first COLL then the EP.

This only works if you're using the front right slot. I don't know how good it will be.

 

[4Chan]

Err, if you're proposing to do OLL like that, the number is algorithms is MUCH higher than what you stated.

 

[BatafCube]

54 algs for WV?
I thought it was 27. d:

This idea seems familiar, as if someone has thought of it before.
My intuition is telling me that your numbers are off. Also, by a wide margin.

There are 27 for when the pair is in the R layer and 27 for when the pair is in the F layer.

NOTE:I am not from America or the UK so please don't yell when i make mistakes.

 

[4Chan]

Ah , I realized it was a mirror, so I deleted the post.

 

[BatafCube]

Err, if you're proposing to do OLL like that, the number is algorithms is MUCH higher than what you stated.

Mathematically 8(the VH algs)*54(WV algs)=432

 

[4Chan]

Hm, okay.
Go for it.

 

[miniGOINGS]

Isn't the exact chance of an OLL skip? Ex 1/x for an OLL skip (I forget) = x number of algs needed.

 

[BatafCube]

Hm, okay.
Go for it.

I don't know.....

 

[Athefre]

It depends on the amount of moves. Since you are creating a pair both in normal Fridrich and this WV+VH idea and both involve recognizing a case (OLL and the WV+VH), the advantage your idea has here is:

Normal Fridrich (Cross, 4 pairs, OLL, PLL) minus the time it takes to insert the pair.

Again, it depends on the amount of moves, the above is considering that the average move count for the memorized cases would be around the same as OLL. WV averages 8 moves, if you can get a move count around that you would have an even greater advantage. Also, the recognition time has to be the same as OLL, which seems possible.

 

[Zarxrax]

I don't see the advantage of this.

With the normal way: Look for the last f2l pair, solve it, look for the OLL, solve it. 2 looks.

With this way, look for the f2l, then START to solve it, but once you are half way through it, look for the oll case, then finish solving the f2l + oll. Its STILL 2 looks, but now you have to memorize hundreds of algs instead of 57.

 

[DavidWoner]

Isn't the exact chance of an OLL skip? Ex 1/x for an OLL skip (I forget) = x number of algs needed.

Not at all. By that logic you have a 1/21 chance of getting a PLL skip, which doesn't even remotely make sense.