How much are you willing to pay if there was ever a BEST cube?

[amostay2004]

I'm sure most of us here agree that no cube is perfect and every cube has its advantages and drawbacks. But let's just say that such a cube actually exists and is the perfect match for you, for example a cube that:

- Never pops in a lifetime
- Cuts corners better than any other cubes out there
- Is a breeze at disassembling/assembling
- Never locks up
- Smoother than every other cubes but not too smooth that you can't control (in short: perfect smoothness for you)
- Has no hardware problems eg. centre caps never fall out
- Never needs lube and will stay smooth for a lifetime
- Will not deteriorate even a little bit in a lifetime
- etc etc.

I'm just giving examples. Some people might not like cubes that cut corners too much, maybe. Just think of it as YOUR perfect cube, not anyone else's. And also assume that there will be no other cube produced in the future that will be better in any way than this perfect cube. Which means if you're not a cube collector and only use for speed purposes, you will only have to purchase this one cube and you're good for life.

So the question now is: how much would you spend on this imaginary perfect cube? State your answers in USD for comparing purposes

My answer:
2x2 - ~$30
3x3 - ~$100
4x4 - ~$100
5x5 - ~$100

Sure a 4x4 and 5x5 would cost much more than a 3x3 to produce but I just love all 3x3 events and a perfect 3x3 cube for me is reallly worth it =)

 

[Edward]

2x2- ~$20
3x3- ~$30
4x4- ~$35
5x5- meh.

 

[ChrisBird]

Id pay a lot for 3x3 and 4x4.
For 2x2 and 5x5 I wouldn't pay much considering I'm fine with the ones I have, but I'd certainly like to have them.

6x6: Infinite. I. Need. Amazing. 6x6. Want. Sub. 3. Average.

7x7: Meh, I'm fine with mine?

 

[Muesli]

I'm from yorkshire, so I'm quite stingy.

I'd probably wait until I got sub-15 averages to get the "Ultimate" cube, so not much.

 

[qqwref]

2x2: $20, don't care much about 2x2
3x3: $1000, if it's perfect for speed and OH and so on I would gladly pay this
4x4: $200
5x5: $35, v-5 is good enough for me
6x6: $200
7x7: $200
also, megaminx: $100

 

[mmMarco17]

$1700 for the lot.

Now, if I could only find me $1694 dollars somewhere..

 

[amostay2004]

5x5: $35, v-5 is good enough for me

That was what I was thinking as well, but I bought a 2nd v-5 when my black one got too loose. So technically I spent $70 in search for a good 5x5, and I'd be willing to pay the extra $30 if it isn't prone to internal lockups and is easier to assemble/disassemble =p AND is slightly smoother yet easier to control :rolleyes:

 

[Lucas Garron]

2x2x2: $64
3x3x3: $256
4x4x4: $128
5x5x5: $128
6x6x6: $128
7x7x7: $128
Square-1: $128
Megaminx: $96
Gigaminx: $192
Pyraminx: $64


Get me a proven perfect cube, and I WILL buy it for $256.

D-II was great out of the box, but I still need the solid/heavy, easy feel of my competition A's.

 

[SkateTracker]

2x2:$20
3x3:$50
4x4:$100
5x5:$100
6x6:$100
7x7:$100

o_o

It'd be more if I wasn't broke and wouldn't have chop off and sell random limbs to buy these cubes.

 

[hyunchoi98]

1x1 uhhh 5 dollars
2x2 $30
3x3 $50
4x4 $60
5x5 $60
6x6, 7x7 $100 each

 

[StachuK1992]

I'd want to buy a perfect magic. One that never breaks, and never locks up or gets too loose or tight.

2x2-40
3x3-80
Magic-60

I wouldn't buy any others, unless they were cheap.

 

[qqwref]

1x1 uhhh 5 dollars

Then have I got a deal for YOU!

 

[JLarsen]

Hahahaha QQ.

2x2- Maybe 5 dollars....
3x3- 50
4x4- 30-40
5x5- 80
6x6- 90
7x7- 100

I'm going with those. Notice I don't like 2x2 and 4x4?

 

[Lucas Garron]

Hahahaha QQ.

2x2- Maybe 5 dollars....
3x3- 50
4x4- 30-40
5x5- 80
6x6- 90
7x7- 100

I'm going with those. Notice I don't like 2x2 and 4x4?

Maybe if you had cood cubes you would.

 

[amostay2004]

Still..$30-40 is not a small amount for something you 'don't like'

 

[MichaelP.]

Hahahaha QQ.

2x2- Maybe 5 dollars....
3x3- 50
4x4- 30-40
5x5- 80
6x6- 90
7x7- 100

I'm going with those. Notice I don't like 2x2 and 4x4?

Why not buy the 2x2 for 10, then sell it to Rowe or someone for quite a bit more?

 

[oskarasbrink]

Just think of it as YOUR perfect cube, not anyone else's

I'm sure some people would try to steal it
but it would've been awesome.
now on topic
'bout 30 USD. i know that better cubes doesn't makes that much of a difference and that i'm already spending too much money on new cubes

 

[rachmaninovian]

2x2: 40
3x3: 50
4x4: 300. my favorite event?
5x5: 35, meh, v-cubes nicely broken in are nice.
6x6: 100
7x7: 150?

 

[thiJUMBA]

some people are highly unreasonable ==" paying over 50 for a perfect 3x3x3
*rich people* ...

i only use the 3x3x3 so i would pay 50 aussie dollars
but i doubt they would sell JUST a rubiks cube for over 50 dollars...

 

[qqwref]

some people are highly unreasonable ==" paying over 50 for a perfect 3x3x3
*rich people* ...

That's not unreasonable at all. The first post pretty much said that it's the best cube you will ever have, and that it will never get worse or wear out. Unless you're very slow, the value of having the best cube is at the very least the cost of every other cube you'll ever have to buy for speedsolving in the future... and if you include the enjoyment, recognition, prizes, records, etc. you can get from being extra good at 3x3, I think paying several hundred dollars is a pretty good deal.