sz35
Regular
I'm now learning ZB (ZBF2L= 114 algs and ZBLL= around 30) and I want to know if there is someone else who learns ZB right now.(besides cubes=life)
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I'm now learning ZB (ZBF2L= 114 algs and ZBLL= around 30) and I want to know if there is someone else who learns ZB right now.(besides cubes=life)
I'm now learning ZB (ZBF2L= 114 algs and ZBLL= around 30) and I want to know if there is someone else who learns ZB right now.(besides cubes=life)
Naaah.
I'm now learning ZB (ZBF2L= 114 algs and ZBLL= around 30) and I want to know if there is someone else who learns ZB right now.(besides cubes=life)
Naaah.
what? and Edward this is not the number of algs in the method, this is how much I know
Well, my goal is ZB, though I am at the moment trying to first get sub-20. I know extended VHF2L (standard 32 algs + 16 otherwise tricky cases) and all of COLL. I have also started generating algs and images and started a document with all the algs I have made so far. I have not made any real effort to remember the algs yet.
I actually am able to recognize the ZB cases when performing a COLL. I just have issues with Anti-Sune, Pi, and H. When the time comes I'll figure out some sort of recognition system.
LOL!
ZBLL is only like 15.4 algs, with mirrors. wut nubs.
I'm now learning ZB (ZBF2L= 114 algs and ZBLL= around 30) and I want to know if there is someone else who learns ZB right now.(besides cubes=life)
no. It's 41 sets of lots of algorithmsI'm confused because of your signature. ZBLL is 41 algorithms?
no. It's 41 sets of lots of algorithmsI'm confused because of your signature. ZBLL is 41 algorithms?
Think ( COLL ) x ( EPLL ).
41 comes from COLL
I'm confused because of your signature. ZBLL is 41 algorithms?