PLL skip? No problem, but...

[Neuromancer]

... did anyone of you get two PLL skips back-to-back?

This just happened to me a few minutes ago.

Greets

 

[cmhardw]

(1/72)^2 = 1/5184 probability of that on a 3x3x3 cube. I think that is rare yes, but not unheard of.

Chris

 

[OOOH]

Ive never had it, thats quite lucky. The chance is only: (1/72)^2 = 0.02%

EDIT: Chris was a bit faster

 

[Neuromancer]

Thx for the replies.

But...
Are you sure, this can be calculated this way (1/72 x 1/72) ?

Thinking:
If someone's exercising 100 solves a day, this should happen nearly every 50 days. That's a period not too big, so this should happen to every cuber who's training in a normal way. Even if someone's training just 50 times a day, this should happen every 100 days, so this would be three times a year.

Did I overlook a fault?

Greets

 

[Stefan]

In other words, if just 100 cubers do just 50 solves a day, you can expect this to happen once a day. So nothing worth mentioning.

 

[qazefth]

I once got 3 PLL skip in a row, but too bad I did time it. And I dont think this as lucky or something, because hand scrambled it, but I got different OLL each time.

 

[AvGalen]

qazefth: you don't consider 3 PLL skips in a row lucky????

 

[qazefth]

yeah maybe, coz it was hand scramble, hmm, one second tought, maybe it is lucky, hehe

 

[blah]

qazefth: you don't consider 3 PLL skips in a row lucky????

Technically, that's as lucky as getting 3 H perms in a row, or any combination of 3 H perms or PLL skips in a row :rolleyes:

 

[AvGalen]

qazefth: you don't consider 3 PLL skips in a row lucky????

Technically, that's as lucky as getting 3 H perms in a row, or any combination of 3 H perms or PLL skips in a row :rolleyes:

No, technically it is just as probable. Lucky is not a technical term.

Let's say that the chances of winning the lotery and chances of getting hit by lightning are both 1/72. I would consider winning the lotery once lucky and winning it 3 times in a row really really really lucky.
I wouldn't consider getting hit by lightning lucky.....
And everyone that calls getting hit by lightning 3 times in a row really really really lucky must be .... the devil

 

[DAE_JA_VOO]

I once got 3 PLL skip in a row, but too bad I did time it.

Yeah I'm pretty sure I've had three PLL skips in a row too. I was driving one day and i remember thinking "Man, how many PLL skips am I going to get? or something to that effect. Like I said though, i'm pretty sure, but not 100%. I've definitely had two PLL skips in a row though.

 

[MTGjumper]

I've had 3 OLL skips in a row. That's (1/216)^3 = 1/10077696. Yeah, that's pretty rare, although I did get two OLL skips in a row on Saturday too

 

[ThatGuy]

my first entire LL skip was on a 4x4 with no AUF.

 

[Cride5]

Entire LL skips on ZZ solves seem to be quite common, I've had 3 so far - none timed unfortunately :rolleyes:

I'm guessing the chances of a LL skip with edges pre-oriented would be 1/#ZBLL cases = 1/494 = ~0.2%, I may be wrong tho.

 

[Johannes91]

I'm guessing the chances of a LL skip with edges pre-oriented would be 1/#ZBLL cases = 1/494 = ~0.2%, I may be wrong tho.

This is a common mistake cubers make. Ignoring AUF, there are actually 27*72=1944 different ZBLL positions, but some are similar, like T-perm, y T-perm, y2 T-perm, and y' T-perm, which can all be solved with the same alg. So the probability to skip ZBLL is 1/1944 ≈ 0.05%.

Some cases are symmetric, like H-perm and N-perm, so they have only 1 or 2 different rotations, which is why the total number is a bit less than 4*494=1976.

 

[Swordsman Kirby]

I'm guessing the chances of a LL skip with edges pre-oriented would be 1/#ZBLL cases = 1/494 = ~0.2%, I may be wrong tho.

This is a common mistake cubers make. Ignoring AUF, there are actually 27*72=1944 different ZBLL positions, but some are similar, like T-perm, y T-perm, y2 T-perm, and y' T-perm, which can all be solved with the same alg. So the probability to skip ZBLL is 1/1944 ≈ 0.05%.

Some cases are symmetric, like H-perm and N-perm, so they have only 1 or 2 different rotations, which is why the total number is a bit less than 4*494=1976.

I expected there to be more than just 32 symmetric positions...

 

[SimonWestlund]

I've had 3 PLL skips in a row in an average of 12.. the rest of the average sucked though..

I've also had OLL skip, PLL skip, OLL skip

 

[Cride5]

I'm guessing the chances of a LL skip with edges pre-oriented would be 1/#ZBLL cases = 1/494 = ~0.2%, I may be wrong tho.

This is a common mistake cubers make. Ignoring AUF, there are actually 27*72=1944 different ZBLL positions, but some are similar, like T-perm, y T-perm, y2 T-perm, and y' T-perm, which can all be solved with the same alg. So the probability to skip ZBLL is 1/1944 ≈ 0.05%.

Some cases are symmetric, like H-perm and N-perm, so they have only 1 or 2 different rotations, which is why the total number is a bit less than 4*494=1976.

Are you counting a solved LL requiring AUF as an LL-skip as well? Ie. would the probability of an LL-skip, including cases requiring U, U' and U2 still be 1/1944, or would it be 4/1944??

 

[Yes We Can!]

Rama Temmink got two in a row:

 

[irontwig]

I'm guessing the chances of a LL skip with edges pre-oriented would be 1/#ZBLL cases = 1/494 = ~0.2%, I may be wrong tho.

This is a common mistake cubers make. Ignoring AUF, there are actually 27*72=1944 different ZBLL positions, but some are similar, like T-perm, y T-perm, y2 T-perm, and y' T-perm, which can all be solved with the same alg. So the probability to skip ZBLL is 1/1944 ≈ 0.05%.

Some cases are symmetric, like H-perm and N-perm, so they have only 1 or 2 different rotations, which is why the total number is a bit less than 4*494=1976.

Are you counting a solved LL requiring AUF as an LL-skip as well? Ie. would the probability of an LL-skip, including cases requiring U, U' and U2 still be 1/1944, or would it be 4/1944??

1/1944.