Advantages of blindfold methods

[KConny]

When will TuRBo go public?

 

[masterofthebass]

I would give Erik at least 1 day to relax. He'll make it public whenever he does. It should be pretty soon.

 

[AvGalen]

This is the general idea about turbo as I understood it:

1) Get 3 edges at 3 fixed positions (orientation doesn't matter so setups are short)
2) Cycle 3 edges using 1 of 8 different algorithms.

This way you solve 2 edges completely (orientation + permutation) at a time

I don't know anything about TuRBo corners

 

[Joël]

pure 3-cycle (as Macky's tutorial describes)

M2/R2
Advantages:
- easy to memorize
- easy setup moves (only M2)
- fast execution with almost no practice

Disadvantages:
- solves only one piece at once

I would like to add that, allthough it looks like a 2-cycle method, this method is close to being a three cycle method. Let me explain:

A person solving the cube with commutator 3 cycles, might use algs like L' U2 L E2 L' U2 L E2. I used this alg and variations when I still did pure Pochmann with T/Jperms. Or... the same kind of thing can be done with M2, of course. For example U R U' M2 U R' U' (...) M2, which is a three cycle. It cycles FD RF BU. M2 uses exactly this idea, only you setup another edge at BU before doing the last M2.

IMO, M2 can be seen as a simplification of a 3 cycle method... It just breaks a more complex problem into two different steps, to make the whole thing easier. Just like speedcubers break down the LL in OLL/PLL to make things easier .

 

[Erik]

This is the general idea about turbo as I understood it:

1) Get 3 edges at 3 fixed positions (orientation doesn't matter so setups are short)
2) Cycle 3 edges using 1 of 8 different algorithms.

This way you solve 2 edges completely (orientation + permutation) at a time

I don't know anything about TuRBo corners

You can check it out now
Joel is right though, M2 is like 3 cycles (pure 3 cycles) just simplified and broken into 2 smaller easier steps, it already proved to be very fast. Kai Jiptner is the fastest one who uses M2 at the moment he did a 1:13 with it!(not R2).

 

[KJiptner]

Kai Jiptner is the fastest one who uses M2 at the moment he did a 1:13 with it!(not R2).

No this is wrong, but I'm probably the 2nd fastest one. The fastest one (i know) is Rafal Guzewicz, he finished 2nd at worlds and has a home record of 59 seconds. On usual solves he can do around 1:20-1:25, I think. He is using M2 edges and 3 Cycle corners.

 

[Erik]

oh sorry then, but you still are one of the fastest BLD solvers with M2