Isn't that pretty much the same as Petrus...?
Also, the way I began was an extremely easy method that used a version of Fridrich.
To make the cross, you orient the white center edges on the yellow center. From there, you'd the edges one by one, so you'd rotate the center to the edge, and move rotate twice so it meets the white center. And you'd repeat that 3x for each center edge.
From there, you'd look for white pieces along the top, and rotate those into place. Once you have the white bottom as well as the bottom row that meets the white done, you'd work on the second layer (F2L). So you'd look for any center edge pieces that don't have yellow on them. Rotate it so that the piece is adjacent to the center of the same color. Then you'd look at the other color on that cubie, and find where on the cube that center is. You'd rotate the top row 1x away from that center. Rotate the corner that has those colors on it (with the white on it too) up, then over the same direction. Rotate the the column back down to preserve your cross. Then move the white piece that you moved up the opposite direction as before 1x. Then simply put the white piece back into it's place, but at the same time, you'll be putting the second layer into place. Repeat for all of the F2L.
So once your at the OLL step, there are only 2 algorithms to memorize, and they're fairly easy. One is F, U, R, U', R', F'. This would be used for anything that doesn't have a yellow cross in it. Also, note that if you ever are able to orient the top so that you have at least 2 yellow center edges at the 12/9 o'clock positions, you should before using the algorithm. Once you get a cross, you'll use R, U, R', U, R, U2, R'. You'd repeat this algorithm until you solve the yellow layer. Also, note that if you ever get an extra yellow sticker in the corner, rotate so that it's in the bottom-left corner, then use the algorithm.
At PLL, there are again only 2 algorithms to memorize. One is R', F, R', B'2, R, F', R', B'2, R'2. This can be used at any time during this step. Note that any time 2 or more pieces of the same color are on a face, you should rotate so that they meet with the corresponding center, then use the algorithm. You can either do this algorithm until you solve the cube or you can use another algorith. This algorith is used whenever at least 3 faces have the corners in the correct places. If one face is solved you'll want to orient the cube so that that face is at the back of the cube. Now look at the face that is "facing" you. If the center edge of that face matches the center of a face on either side of the cube, remember where. So for example, If I have a red face except for one blue center edge piece, then I'll look for where the blue center is. For me it's on the left. So now this is what I do: F2, since blue was on the left, I move the white to the left (above the blue center), then I do L, R', F2, L', R, now since the blue was on the left, I move the white to the left again (not above the blue this time tho, only rotate the top once), then simply rotate F2, and the cube should be done. Now, if the center was on the right instead of the left, I would rotate things to the right instead. Now if the center was on the opposite side of the cube, all you'd do is just pick a random side you want to rotate to. Then you should find that one face will be completed and the cube should be able to be solved by using the above algorithm.
That's it. Seems like a lengthy explanation but it really is simple, and allows for relatively quick solves. Once you get it down and are working on at least a somewhat good cube, you should be able to get times of around a minute or so at least, that's what I average right now, and I've only been working for a few weeks.
