DynaXT
Veteran
Why are you from the Middle Ages all of a sudden?
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'Tis just for formality. And because it's a formal... um, event.Why are you from the Middle Ages all of a sudden?
They shall be online, either in this thread or the competitor PM groupare we going to submit our times online or elswere
Going back from the beginning, what's the prize?The time hath come. The first X Games on the SpeedSolving.com forums shall commence on March 14th. It is designed to be a new kind of game, one with high stakes and lots of cubing.
The games shall begin on March 14th, 2022. Each day, there will be a new challenge, and whoever gets the slowest time gets eliminated. Overall, there are 21 challenges, ending April 4th, as follows:
Day One (Pi Day) (20 competitors remain.)
Solve a 3x3 and post thy time.
Day Two (19 competitors remain.)
Solve a 3x3 One-Handed and post thy time.
Day Three (18 competitors remain.)
Solve a 2x2 with only thy non-OH hand and post thy time.
Day Four (17 competitors remain.)
Solve a 4x4 (or 6 3x3s) and post thy time.
Day Five (16 competitors remain.)
Three random players have their Day One results compared and the fastest one chooses one person to eliminate.
Day Six (15 competitors remain.)
Perform 100 moves on any cube and post thy time.
Day Seven (14 competitors remain.)
Perform seven 3x3 solves and add up thy times. Then post thy cumulative time.
Day Eight (13 competitors remain.)
Perform eight 2x2 solves and add up thy times. Then post thy cumulative time.
Day Nine (12 competitors remain.)
Solve a megaminx, or perform eight 3x3 solves and add up thy times. Then post thy time or cumulative time.
Day Ten (11 competitors remain.)
Record how long it takes you to clap once, then solve a 2x2, then a 3x3, then a 4x4, and post thy cumulative time.
Day Eleven (10 competitors remain.)
Record how long it takes you to perform a T Permutation on a 3x3, then post thy time.
Day Twelve (9 competitors remain.)
Five random competitors are chosen, and one receives 1 immunity to be used on any one day before Day Sixteen. Each competitor's Day Eight and Day Nine results are added
up, and whoever hath the best cumulative result chooses one person to eliminate.
Day Thirteen (8 competitors remain.)
Solve a 5x5, or perform twelve 3x3 solves and add up thy times. Then post thy time or cumulative time.
Day Fourteen (7 competitors remain.)
Perform thirteen 3x3 solves, add them up, and divide by seven. Then perform five 2x2 solves, add the worst three up, and multiply by six. Then add the two results up and post all
thy times, most importantly the final result.
Day Fifteen (6 competitors remain.)
Look on YouTube for a unique video with a Rubik's Cube in it and embed it here. Whoever posts the video with the least views gets eliminated.
Day Sixteen (5 competitors remain.)
Take apart a 3x3 and record how long it takes you to put it together in the solved position, then post thy time.
Day Seventeen (4 competitors remain.)
You will all be assigned one scramble, and whoever finds the shortest solution in one hour chooses one player to eliminate.
Day Eighteen (3 competitors remain.)
Time how fast you can solve the cross on a 3x3. Whoever gets the slowest result hath to add a second to their time on Day Nineteen.
Day Nineteen (3 competitors remain.)
Solve a 2x2. Then post thy time.
Day Twenty (2 competitors remain.)
Both competitors perform an Average of 12 solves on 3x3, and whoever gets the fastest result decides whether they shall multiply their Day Twenty-One time by 0.9, or multiply
the other person's Day Twenty-One time by 1.1.
Day Twenty-One (2 competitors remain.)
Both competitors perform twelve an Average of 12 solves on 3x3, and whoever gets the slowest result (counting modifications from Day Twenty) gets eliminated.
Day Twenty-Two (1 competitor wins.)
The winner receives a prize, which as of March 2nd hath yet to be determined.
To begin the games, we need 20 competitors. The Google Form is linked here. Sign up if you want a rather... different... cubing challenge.
sounds cool, i signed upThe time hath come. The first X Games on the SpeedSolving.com forums shall commence on March 14th. It is designed to be a new kind of game, one with high stakes and lots of cubing.
The games shall begin on March 14th, 2022. Each day, there will be a new challenge, and whoever gets the slowest time gets eliminated. Overall, there are 21 challenges, ending April 4th, as follows:
Day One (Pi Day) (20 competitors remain.)
Solve a 3x3 and post thy time.
Day Two (19 competitors remain.)
Solve a 3x3 One-Handed and post thy time.
Day Three (18 competitors remain.)
Solve a 2x2 with only thy non-OH hand and post thy time.
Day Four (17 competitors remain.)
Solve a 4x4 (or 6 3x3s) and post thy time.
Day Five (16 competitors remain.)
Three random players have their Day One results compared and the fastest one chooses one person to eliminate.
Day Six (15 competitors remain.)
Perform 100 moves on any cube and post thy time.
Day Seven (14 competitors remain.)
Perform seven 3x3 solves and add up thy times. Then post thy cumulative time.
Day Eight (13 competitors remain.)
Perform eight 2x2 solves and add up thy times. Then post thy cumulative time.
Day Nine (12 competitors remain.)
Solve a megaminx, or perform eight 3x3 solves and add up thy times. Then post thy time or cumulative time.
Day Ten (11 competitors remain.)
Record how long it takes you to clap once, then solve a 2x2, then a 3x3, then a 4x4, and post thy cumulative time.
Day Eleven (10 competitors remain.)
Record how long it takes you to perform a T Permutation on a 3x3, then post thy time.
Day Twelve (9 competitors remain.)
Five random competitors are chosen, and one receives 1 immunity to be used on any one day before Day Sixteen. Each competitor's Day Eight and Day Nine results are added
up, and whoever hath the best cumulative result chooses one person to eliminate.
Day Thirteen (8 competitors remain.)
Solve a 5x5, or perform twelve 3x3 solves and add up thy times. Then post thy time or cumulative time.
Day Fourteen (7 competitors remain.)
Perform thirteen 3x3 solves, add them up, and divide by seven. Then perform five 2x2 solves, add the worst three up, and multiply by six. Then add the two results up and post all
thy times, most importantly the final result.
Day Fifteen (6 competitors remain.)
Look on YouTube for a unique video with a Rubik's Cube in it and embed it here. Whoever posts the video with the least views gets eliminated.
Day Sixteen (5 competitors remain.)
Take apart a 3x3 and record how long it takes you to put it together in the solved position, then post thy time.
Day Seventeen (4 competitors remain.)
You will all be assigned one scramble, and whoever finds the shortest solution in one hour chooses one player to eliminate.
Day Eighteen (3 competitors remain.)
Time how fast you can solve the cross on a 3x3. Whoever gets the slowest result hath to add a second to their time on Day Nineteen.
Day Nineteen (3 competitors remain.)
Solve a 2x2. Then post thy time.
Day Twenty (2 competitors remain.)
Both competitors perform an Average of 12 solves on 3x3, and whoever gets the fastest result decides whether they shall multiply their Day Twenty-One time by 0.9, or multiply
the other person's Day Twenty-One time by 1.1.
Day Twenty-One (2 competitors remain.)
Both competitors perform twelve an Average of 12 solves on 3x3, and whoever gets the slowest result (counting modifications from Day Twenty) gets eliminated.
Day Twenty-Two (1 competitor wins.)
The winner receives a prize, which as of March 2nd hath yet to be determined.
To begin the games, we need 20 competitors. The Google Form is linked here. Sign up if you want a rather... different... cubing challenge.
Braging rights, probablyGoing back from the beginning, what's the prize?
Unadulterated cloutGoing back from the beginning, what's the prize?
It hath been decided. This year, since it is 2022, the prize shall be a $22 gift card to a puzzle store of your choice.Going back from the beginning, what's the prize?
Can't wait until 2099.It hath been decided. This year, since it is 2022, the prize shall be a $22 gift card to a puzzle store of your choice.
Dost thou mean 2090? 2021 subtracted from 2100 is 79, but 2021 subtracted from 2090 is 69.im really dreading 2100
Whatever happen to formality? Verily I say unto you that thy knowledge of medieval language and its most proper usage is catastrophically wretched and I beg of you to implode thy ways and commit thy own self to integrity in upholding these words of Ole.Dost thou mean 2090? 2021 subtracted from 2100 is 79, but 2021 subtracted from 2090 is 69.
2100 | 2090
-2021 | -2021
--------- | ---------
79 | 69
Whatever happen to formality? Verily I say unto you that thy knowledge of medieval language and its most proper usage is catastrophically wretched and I beg of you to implode thy ways and commit thy own self to integrity in upholding these words of Ole.
Take apart a 3x3